How does the law of conservation of mass apply to this reaction: C2H4 + O2 → H2O + CO2?
CHHHCHHOH +OO -> COO + HHO
OO HHO
HHO
Your balanced equation will be
CH3CH2OH +2O2 -> COO + 3H2O
Hope that makes sense
The above is to show how I figure it out
I don’t understand Spanish I don’t understand Spanish I don’t understand Spanish
The first option. NaOH and H3PO4. This is an hydroxide and one acid. The [OH] from NaOH and the [H] from the H3PO4 will form water, while PO4 and Na combine to form Na3PO4, as per this reaction:
3<span> NaOH + H3PO4
= 3 H2O + Na3PO4</span>
Answer:
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆
Explanation:
The rate of effusion of two gases A and B can be expressed by <em>Graham's law</em>:
![\frac{EffusionRateA}{EffusionRateB}=\sqrt{\frac{M_{B}}{M_{A}} }](https://tex.z-dn.net/?f=%5Cfrac%7BEffusionRateA%7D%7BEffusionRateB%7D%3D%5Csqrt%7B%5Cfrac%7BM_%7BB%7D%7D%7BM_%7BA%7D%7D%20%7D)
Where M is the molar mass, and in this case A is ²³⁵UF₆ while B is ²³⁸UF₆.
So now we <u>calculate the molar mass of each mass</u>:
²³⁵UF₆ ⇒235 + 6*19 = 349 g/mol
²³⁸UF₆ ⇒238 + 6*19 = 352 g/mol
Putting the data in Graham's law:
= 1.0043
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆.