Answer:
A) Oxidized
B) Reduced
C) Oxidized
D) Oxidized
Explanation:
A) Cu becomes Cu²⁺
oxidation state increased from 0 to +2. It gets oxidize.
B) Sn⁺⁴ becomes Sn²⁺
oxidation state decreased from +4 to +2. It gets reduced.
C) Cr³⁺ becomes Cr⁺⁶
oxidation state increased from +3 to +6. It gets oxidize.
D) Ag becomes Ag⁺
oxidation state increased from 0 to +1. It gets oxidize.
Oxidation:
Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.
Reduction:
Reduction involve the gain of electron and oxidation number is decreased.
<em>Consider the following reactions.
</em>
4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl
the oxidation state of copper is changed from +2 to +1 so copper get reduced.
CO + H₂O → CO₂ + H₂
the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.
Answer:
H₂ (g) + O₂ (g) ⇒ H₂O (g)
Explanation:
Hydrogen and oxygen gas both exist as diatomic molecules. The water is in gaseous state due to the heat given off by the combustion reaction.
The answer is C. Ionic and covalent bonding exists in the same compound and intermolecular forces exist between different compounds. And that is way called intermolecular forces.
An empirical formula is the chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms.
For example the molecule 'CH2O' is the empirical formula for glucose.
