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3 years ago

How many sucrose molecules will be in 250 grams

Chemistry

1 answer:

sasho [114]3 years ago

6 0

<h2>Answer:</h2>

We will need to know Avogadro's number and the molar mass of sucrose for this problem to do dimensional analysis.

Avogadro's number: 6.022 × 10²³ molecules
Molar mass of sucrose: 342.2965 g/mol

250g × $\frac{1 mol}{342.297g}$ × $\frac{6.022 * 10^{23} molecules}{1 mol}$ = 4.398 molecules

There are 4.398 sucrose molecules in 250 grams of sucrose.

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Name the two products formed when hydrocarbons burn in oxygen

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Answer:

Carbon dioxide (co2)

Water (H2O)

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It differs because it shows different volume of information and it gives a different point of indicanton of numbers.

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3 years ago

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Assuming 100% dissociation, calculate the freezing point and boiling point of 2.60 m K3PO4(aq).

Serga [27]

To find the freezing point, you use the following formula

fp solution= fp solvent - Δfp solution

fp solvent= 0 C (since the solvent was not stated, you can assume is water which freezing point is 0 degree celsius)

but first, we need to find the depression in freezing point (Δfp solution)

Δfp solution= Kf x i x m, where Kf is constant for the solvent, i is the number of particles produced by the solute and m is the molality of the solution.

Kf= 1.86 for water
i= 4 , becausethe solute breaks into 4 ions, K3PO4---> 3K+ + PO4-3
m= 2.60

Δfp solution= (1.86) (4) (2.60)= 19.3 C

fp solution= 0 - 19.3C= -19.3C


for boiling point, we use a similar formula and way to solve it.

Δbp solution= bp solvent + Δbp solution

bp solvent= 100 C for water

to find the elevation boiling point (Δbp soln) is equal to:

Δbp solution= Kb x i x m

Kb= 0.512
i= 4
m= 2.60

Δbp solution= (0.512) (4) (2.60)= 5.32 C

bp solution= 100C + 5.32C= 105.32 C

6 0

4 years ago

Consider 2.4 moles of a gas contained in a 4.0 L bulb at a constant temperature of 32°C. This bulb is connected to an evacuated

Luden [163]

Complete Question

The complete question is shown on the first uploaded image

Answer

As the valve is opened , the gas will flow into the empty container until the both containers have the same pressure

$\Delta H = 0\ , \Delta E = 0 , q= 0 , w= 0$

The driving force for this process is the increase in entropy this is because the movement of the internal energy of the gas into a larger volume, what this does is that it increases the amount of disorder(entropy).

Explanation

In order to obtain the parameter in the part B of the question we are first obtain the initial pressure, using the ideal gas equation

$P = \frac{nRT}{V}$

$P = \frac{(2.4mol)(0.0821\frac{1 atm}{K \cdot \ mol} )}{4.0L}$

$P =15 \ atm$

The next thing is to obtain the new pressure of the gas , using boyle's law

$P_1V_1 = P_2V_2$

$P_2 = \frac{P_1 V_1}{V_2}$

$P_2 = \frac{(15 \ atm)(4.0L)}{24.0 L}$

$P_2 = 2.5 \ atm$

Since the this process is isothermal , the change in heat is equal to zero

i.e q = 0 J

The workdone to move the gas to the other container is zero because the the pressure at this second container is zero due to the fact that it is a vacuum

i.e $w = -P_{external} \Delta V$

$=-(0 \ atm) (24.0 - 4.0L)$

$= 0L \cdot atm$

Since the change in heat is zero and the workdone is zero then the change in internal energy is equal to 0

This is because the change in internal energy is equal to a summation of change in heat and the workdone

i.e $\Delta E = q + w$

$= 0J$

Generally the change in enthalpy is mathematically represented as

$\Delta H = n C_p \Delta T$

Since the temperature is zero this means that the change in temperature is zero , substituting this value for change in temperature into the equation for change in enthalpy

$\Delta H = n C_p (0)$

$= 0J$

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4 years ago

explain why iron can displace copper from copper II nitrate solution, but copper cannot displace iron from iron III nitrate solu

mihalych1998 [28]

Answer:

Iron metal is more reactive than copper.

Explanation:

Iron metal is more reactive than copper. ... Cu is less reactive than iron, therefore, cannot replace iron from iron sulphate (FeSO4). we have already seen that iron is more reactive than copper. So that means that in this reaction, copper is less reactive than iron. That means copper cannot displace iron. It cannot kick out iron from a sulfate.

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3 years ago