Answer:
53.85%
Explanation:
Data obtained from the question include:
Mass of antimony (Sb) = 27.6g
Mass of Fluorine (F) = 32.2g
Mass of compound = 59.8g
Percentage composition of fluorine (F) =..?
The percentage composition of fluorine can be obtained as follow:
Percentage composition of fluorine = mass of fluorine/mass of compound x 100
Percentage composition of fluorine = 32.2/59.8 x 100
= 53.85%
Therefore, the percentage composition of fluorine in the compound is 53.85%
Answer:
6moles of Li : 1 mole of N₂
Explanation:
The reaction equation is given as:
6Li + N₂ → 2Li₃N
Mole ratio of Li to N₂;
From the balanced reaction equation:
6 moles of Li will react with 1 mole of N₂;
The mole ratio is:
6moles of Li : 1 mole of N₂
N2 + 3H2 ----> 2NH3
<span>you can see 3 moles H2 reacts to form 2 moles NH3 </span>
<span>Therefore moles NH3 = 2 / 3 x moles H2 </span>
<span>= 2/3 x 12.0 mol </span>
<span>= 8.00 mol NH3 hope this help</span>
homeostatic imbalance is the answer, because it's when the internal environment cannot remain in equilibrium.