Answer:
The percentage (by mass) of KBr in the original mixture was 33.1%.
Explanation:
The mixture of KCl and KBr has a mass of 3.595g, thus the sum of the moles of KCl (<em>x</em>) multiplied by it molar mass (74.5g/mol) and the moles of KBr (<em>y</em>) multiplied by it molar mass (119g/mol) is the total mass of the mixture:

Also, after the conversion of KBr into KCl, the total mass of 3.129 g is only from KCl moles, hence

But the 0.042 moles came from the originals KCl and KBr moles, thus

Now it is possible to propose a system of equations:


Solving the system of equations,

0.010 moles of KBr multiplied it molar mass is

Therefore, the percentage (by mass) of KBr in the original mixture was:
%
Explanation:
Teniendo en cuenta los numeros de oxidacion negativos de cada uno
P:fosforo(-3)
S:Azufre (-2)
Br:Bromo (-1)
Y el H: hidrogeno con una valencia
positiva de +1
los compuesto que se formaran son los siguientes
1 H3P= fosfuro de hidrogeno
2 H2S= sulfuro de hidrogeno
3 HBr= Acido bromhidrico
ESPERO ABERTE AYUDADO ;D
You should try to strt a conversation with him or say hi introduce yourself or ask him how hes doing just talk to him i guess
Answer:
Kinetic energy
Explanation:
Objects or particles under motion posses energy in the form of kinetic energy which is directly proportional to the square of the velocity of the given particle.
E= 1/2mv² where m is the mass of the particle and v the velocity of the particle.