Answer:
Yes, the given instance is an example of a trade-off.
Explanation:
- The trade-off seems to be a strategy to minimize or surrender one or more favorable results in consideration for increasing either receiving other favorable results to optimize cumulative benefit or efficacy within such conditions.
- The above is indeed a trade-off since the participants are experimenting in exchange again for ice cream individuals have to enjoy. The ice cream manufacturer always gets a review of the technician in exchange for free ice cream.
Answer:
54.30 grams acetone
Explanation:
(0. 935 mol)*(58.08 g/mole) = 54.30 grams acetone
Barium-131's radiation level won't reach 1/4 of its initial level for 24 hours.
ln[A] t = -kt + ln[A] 0 is the integrated rate rule for the first-order reaction A's products.
A straight line is produced when the natural log of [A] is plotted as a function of time since this equation has the form y = mx + b.
How is the length of a half-life determined?
The amount of time needed for the reactant concentration to drop to half its initial value is known as the half-life of a reaction. A first-order reaction's half-life is a constant that is correlated with its rate constant:
t 1/2 = 0.693/k.
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Answer:
A single compound is simultaneously oxidized and reduced.
Explanation:
In chemistry, disproportionation is a simultaneous oxidation and reduction of a single chemical specie.
What this means is that; in a disproportionation reaction, only one compound is both oxidized and reduced. This implies that two products are formed during disproportionation. One is the oxidized product while the other is the reduced product.
Consider the disproportionation of CuCl shown below;
2CuCl -----> CuCl2 + Cu
Here, CuCl2 is the oxidized product while Cu is the reduced product.
