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Cerrena [4.2K]
4 years ago
14

Tom left for his friend's house. He drove 60 km in an hour. When he got to John's house, he wondered how fast he had been drivin

g. What formula would he use to determine his speed?
Physics
1 answer:
ser-zykov [4K]4 years ago
7 0

Answer: Tom drove 60 km/hr fast

Speed = Distance traveled / time taken

Explanation:

Given that:

Distance traveled by Tom = 60 km

Time taken by Tom = 1 hour

Speed = ?

Since speed is obtained by dividing distance traveled by the time taken, hence the formula to use is as follows:

speed = distance / time

Speed = 60 km / 1 hour

Speed = 60 km/hr

Thus, Tom had been driving 60 km/hr fast, using the formula "speed = distance / time"

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An object moves with constant acceleration 4.00 m/s^2 and over a time interval reaches a final velocity of 12.0 m/s.
Bas_tet [7]
A) We can use the equation of motion:
2as = v² - u²
s = (12² - (-6)²) / 2 x 4
s = 13.5 m

b) We calculate the time over which this displacement occurred using:
v = u + at
t = (12 - -6)/4
t = 4.5 seconds
Assuming the average speed equal to:
(12 + 6) /2 = 9 m/s
average speed = total distance/total time
total distance = 9 x 4.5
= 40.5 m
7 0
3 years ago
What is the pressure of a 300 lb. object on a 100 sq. in. area?
denis23 [38]

Answer:

D. 3 psi

Explanation:

Pressure is defined as force acting per unit area and is numerically expressed as:

P= \frac {F}{A}

where P represent pressure, F is force and A is area where the force acts. Substituting 300 lb for force and 100 sq.in for area then pressure,

P=\frac {300 lb}{100 in^{2}}= 3 \ psi

Therefore, from the choices given, option D, 3psi is the right choice.

3 0
3 years ago
If anyone don't mind answering-:
Dennis_Churaev [7]

Answer:

1. inference

2. analysis

others I don't have any idea sorry

5 0
3 years ago
A softball player swings a bat, accelerating it from rest to 2.6 rev/srev/s in a time of 0.20 ss . Approximate the bat as a 0.90
svetoff [14.1K]

Answer:

\tau=22.13Nm

Explanation:

information we have:

mass: m=0.9kg

lenght: L=0.95m

frequency: f=2.6rev/s

time: t=0.2s

and from the information we have we can calculate the angular velocity \omega. which is defined as

\omega=2\pi f

\omega=2\pi (2.6rev/s)\\\omega=16.336 rev/s

----------------------------

Now, to calculate the torque

We use the formula

\tau=I \alpha

where I  is the moment of inertia and \alpha is the angular acceleration

moment of inertia of a uniform rod about the end of it:

I=\frac{1}{3}mL^2

substituting known values:

I=\frac{1}{3} (0.9kg)(0.95m)^2\\I=0.271kg/m^2

for the torque we also need the acceleration \alpha which is defined as:

\alpha=\frac{\omega}{t}

susbtituting known values:

\alpha=\frac{16.336rev/s}{0.2s} \\\alpha=81.68rev/s^2

and finally we substitute I and  \alpha  into the torque equation \tau=I \alpha:\tau=(0.271kg/m^2)(81.68rev(s^2)\\\tau=22.13Nm

5 0
4 years ago
A wire carries a steady current of 2.20 A. A straight section of the wire is 0.750 m long and lies along the y axis within a uni
Akimi4 [234]

Answer:

2.805 N

Explanation:

Given,

Current, I = 2.20 A

Length of the section,L = 0.750 m

Magnetic field, B = 1.70 T

θ = 90°

Magnetic Force,F = ?

We know,

F = IBL sin θ

F = 2.20 x 1.70 x 0.750 x sin 90°

F = 2.805 N

Hence, magnetic force is equal to 2.805 N.

6 0
3 years ago
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