Time taken by the package to reach the sea level= 13.7 s
height=h=925 m
initial velocity along vertical= vi=0
acceleration due to gravity=g=9.8 m/s^2
using the kinematic equation h= Vi*t + 1/2 gt^2
925=0(t)+1/2 (9.8)t^2
4.9 t^2=925
t= 13.7 s
D. It is personal in style.
Answer:
The kinetic energy of the merry-go-round is
.
Explanation:
Given:
Weight of the merry-go-round, 
Radius of the merry-go-round, 
the force on the merry-go-round, 
Acceleration due to gravity, 
Time given, 
Mass of the merry-go-round is given by

Moment of inertial of the merry-go-round is given by

Torque on the merry-go-round is given by

The angular acceleration is given by

The angular velocity is given by

The kinetic energy of the merry-go-round is given by

Well,
A = T or U
C = G
G = C
T or U = A
So it would be like this;
DNA Sequence: GCTAATTGCATCCGA
The Complementary Sequence: CGATTAACGTAGGCT
Hope this helped :)
Answer:
a) x_{cm} = m₂/ (m₁ + m₂) d
, b) x_{cm} = 52.97 pm
Explanation:
The expression for the center of mass is
= 1 / M ∑
Where M is the total masses, mI and xi are the mass and position of each element of the system.
Let's fix our reference system on the oxygen atom and the molecule aligned on the x-axis, let's use index 1 for oxygen and index 2 for carbon
x_{cm} = 1 / (m₁ + m₂) (0+ m₂ x₂)
Let's reduce the magnitudes to the SI system
m₁ = 17 u = 17 1,661 10⁻²⁷ kg = 28,237 10⁻²⁷ kg
m₂ = 12 u = 12 1,661 10⁻²⁷ kg = 19,932 10⁻²⁷ kg
d = 128 pm = 128 10⁻¹² m
The equation for the center of mass is
x_{cm} = m₂/ (m₁ + m₂) d
b) let's calculate the value
x_{cm} = 19.932 10⁻²⁷ /(19.932+ 28.237) 10⁻²⁷ 128 10-12
x_{cm} = 52.97 10⁻¹² m
x_{cm} = 52.97 pm