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sveticcg [70]
3 years ago
14

Light is an example of something that travels in waves. Light waves come in many different varieties, and can be seen as many di

fferent colors. What is the main difference between a light wave that produces the color blue and a light wave that produces the color red? A. Magnitude B. Wavelength C. Direction D. Amplitude
Physics
2 answers:
Anuta_ua [19.1K]3 years ago
6 0

Answer:

Option (B)

Explanation:

Light is a form of electro-magnetic waves. This light wave has distinct range of wavelength that allows it to form different colors of light. This means that the color of the light produces depending on the amount of wavelength it comprises.

The visible light ranges from Violet to Red, and this is observed as different colors when each of these electromagnetic waves strikes our eyes at a certain angle. The violet light has the shortest wavelength of about 410 nm, where the red light has the highest wavelength of about 650 nm.

Thus, the correct answer is option (B).

RoseWind [281]3 years ago
6 0

Answer:

option (B)

Explanation:

Light waves are electromagnetic waves which can be seen by our eye.

The white light contains seven colours of light which are given below:

Violet

Indigo

Blue

Green

Yellow

Orange

Red

This is the order of increasing wavelength and the decreasing frequency.

So, the wavelength of blue light and the red light is different.

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Consider a uniformly charged sphere of radius Rand total charge Q. The electric field Eout outsidethe sphere (r≥R) is simply tha
AlexFokin [52]

1) Electric potential inside the sphere: \frac{Q}{8\pi \epsilon_0 R}(3-\frac{r^2}{R^2})

2) Ratio Vcenter/Vsurface: 3/2

3) Find graph in attachment

Explanation:

1)

The electric field inside the sphere is given by

E=\frac{1}{4\pi \epsilon_0}\frac{Qr}{R^3}

where

\epsilon_0=8.85\cdot 10^{-12}F/m is the vacuum permittivity

Q is the charge on the sphere

R is the radius of the sphere

r is the distance from the centre at which we compute the field

For a radial field,

E(r)=-\frac{dV(r)}{dr}

Therefore, we can find the potential at distance r by integrating the expression for the electric field. Calculating the difference between the potential at r and the potential at R,

V(R)-V(r)=-\int\limits^R_r  E(r)dr=-\frac{Q}{4\pi \epsilon_0 R^3}\int r dr = \frac{-Q}{8\pi \epsilon_0 R^3}(R^2-r^2)

The potential at the surface, V(R), is that of a point charge, so

V(R)=\frac{Q}{4\pi \epsilon_0 R}

Therefore we can find the potential inside the sphere, V(r):

V(r)=V(R)+\Delta V=\frac{Q}{4\pi \epsilon_0 R}+\frac{-Q}{8\pi \epsilon_0 R^3}(R^2-r^2)=\frac{Q}{8\pi \epsilon_0 R}(3-\frac{r^2}{R^2})

2)

At the center,

r = 0

Therefore the potential at the center of the sphere is:

V(r)=\frac{Q}{8\pi \epsilon_0 R}(3-\frac{r^2}{R^2})\\V(0)=\frac{3Q}{8\pi \epsilon_0 R}

On the other hand, the potential at the surface is

V(R)=\frac{Q}{4\pi \epsilon_0 R}

Therefore, the ratio V(center)/V(surface) is:

\frac{V(0)}{V(R)}=\frac{\frac{3Q}{8\pi \epsilon_0 R}}{\frac{Q}{4\pi \epsilon_0 R}}=\frac{3}{2}

3)

The graph of V versus r can be found in attachment.

We observe the following:

- At r = 0, the value of the potential is \frac{3}{2}V(R), as found in part b) (where V(R)=\frac{Q}{4\pi \epsilon_0 R})

- Between r and R, the potential decreases as -\frac{r^2}{R^2}

- Then at r = R, the potential is V(R)

- Between r = R and r = 3R, the potential decreases as \frac{1}{R}, therefore when the distance is tripled (r=3R), the potential as decreased to 1/3 (\frac{1}{3}V(R))

Learn more about electric fields and potential:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

7 0
3 years ago
I need help please...
Natalka [10]
No cluuuueee :/ sowwwwyyy but good luck
6 0
3 years ago
Read 2 more answers
Please help me! I don’t get this
goldfiish [28.3K]

The answer will be

(1) correct

(2) correct

(3) the force of the soccer ball on the net

(4) Will not change

Hope this help

4 0
3 years ago
Read 2 more answers
"A block of metal weighs 40 N in air and 30 N in water. What is the buoyant force on the block due to the water? The density of
Alja [10]

Answer:

buoyant force on the block due to the water= 10 N

Explanation:

We know that

buoyant force(F_B) on a block= weight of the block in air (actual weight) - weight of block in water.

Given:

A block of metal weighs 40 N in air and 30 N in water.

F_B =  40-30= 10 N

therefore,  buoyant force on the block due to the water= 10 N

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3 years ago
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An object is 3.0 cm from a concave mirror, with a focal length of 1.5 cm. Calculate the image distance. Remember to include your
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Answer:

Construct a quadrilateral ABCD, where

Construct a quadrilateral ABCD, whereAB = 4 cm, BC = 5 cm, CD = 6.5 cm and angle B = 105° and angle C = 80°

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