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Sveta_85 [38]
3 years ago
11

What is the pressure of a 300 lb. object on a 100 sq. in. area?

Physics
1 answer:
denis23 [38]3 years ago
3 0

Answer:

D. 3 psi

Explanation:

Pressure is defined as force acting per unit area and is numerically expressed as:

P= \frac {F}{A}

where P represent pressure, F is force and A is area where the force acts. Substituting 300 lb for force and 100 sq.in for area then pressure,

P=\frac {300 lb}{100 in^{2}}= 3 \ psi

Therefore, from the choices given, option D, 3psi is the right choice.

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An example of a folkway violation would be driving 70 mph in a 50-mph zone. Group of answer choices True False
shutvik [7]

Answer:

Yes.

Explanation:

That is also a law violation.

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3 years ago
WILL GIVE BRAINLIEST AND 30 POINTS!
mariarad [96]

Answer:

Gallium

Explanation:

Gallium is one such element used as a do/pant in a p-type semiconductor.

A do/pant is an impurity added to a semi-conductor used to alter its properties. Semi-conductors have a wide range of applications. They will conduct heat and electricity only under certain conditions. This property is highly desirable and find a wide application in electronics.

For p-type conductors, they are best do/ped with elements with 3 valence electrons. These are group 3 elements. From the choices, only gallium belongs to this group.

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8 0
3 years ago
What is a force that resist the motion of one force over another​
Deffense [45]

Answer:

Friction is a surface force that opposes relative motion.

7 0
3 years ago
Read 2 more answers
Two cars are moving towards each other and sound emitted by first car with real frequency of 3000 hertz is detected by a person
sertanlavr [38]

Answer:

 v ’= 21.44 m / s

Explanation:

This is a doppler effect exercise that changes the frequency of the sound due to the relative movement of the source and the observer, the expression that describes the phenomenon for body approaching s

           f ’= f (v + v₀) / (v-v_{s})

where it goes is the speed of sound 343 m / s, v_{s} the speed of the source v or the speed of the observer

in this exercise both the source and the observer are moving, we will assume that both have the same speed,

                v₀ = v_{s} = v ’

we substitute

               f ’= f (v + v’) / (v - v ’)

               f ’/ f (v-v’) = v + v ’

               v (f ’/ f -1) = v’ (1 + f ’/ f)

               v ’= (f’ / f-1) / (1 + f ’/ f) v

               v ’= (f’-f) / (f + f’) v

let's calculate

                v ’= (3400 -3000) / (3000 +3400) 343

                v ’= 400/6400 343

                v ’= 21.44 m / s

3 0
3 years ago
What is the mass if an object moving with a speed of 9m/s and a kinetic energy if 2000 J​
stepladder [879]

Solve for mass:

m= 2k/v(squared)

m=2000(2)/9(squared))

m=49.383 kilograms

7 0
3 years ago
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