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OlgaM077 [116]
3 years ago
8

If anyone don't mind answering-:

Physics
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

1. inference

2. analysis

others I don't have any idea sorry

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Using F=ma, explain why a train is more difficult to start moving and more difficult to bring to a stop than an average sized ca
seropon [69]

Answer:

M_Train>> m_car    a_train <a_car

Explanation:

To start the movement of the train or the car, the motorcycle applies a force on the wheels, which starts the acceleration in the case of the train, it has a much greater mass than that of the car, for which to obtain the same acceleration necessary a much greater force

         a = F / m

as the mass of the train is greater than that of the car.

         a_train <a_car

Something similar happens when the vehicles stop, the engine stops applying force forward and the brakes apply a force backward that creates a negative acceleration that slows down, again as the mass of the train is much greater than the of the car its negative acceleration is much less.

   

It is good to clarify that to compensate for this the trains have a braking system on all wheels

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A woman can row a boat at 4.0 mph is still water.
vovikov84 [41]

Answer:

1) \theta=120^{\circ} from the positive x-axis.

2) t=20\ min

Explanation:

Given:

speed of rowing in still water, v=4\ mph

1)

speed of water stream, v_s=2\ mph

we know that the direction of resultant of the two vectors is given by:

tan\ \beta=\frac{v.sin\ \theta}{v_s+v.cos\ \theta}

where:

\beta=the angle of resultant vector from the positive x-axis.

\theta = angle between the given vectors

When the rower wants to reach at the opposite end then:

\beta =90^{\circ}

so,

tan\ 90^{\circ}=\frac{v.sin\ \theta}{v_s+v.cos\ \theta}

\Rightarrow v_s+v.cos\ \theta=0

2+4\times cos\ \theta=0

cos\ \theta=-\frac{1}{2}

\theta=120^{\circ} from the positive x-axis.

2)

Now the resultant velocity of rowing in the stream:

v_r=\sqrt{v^2+v_s^2+2\times v.v_s.cos\ \theta}

v_r=\sqrt{4^2+2^2+2\times 4\times 2\times cos\ 120}

v_r=12\ mph

Therefore time taken to cross a 4 miles wide river:

t=\frac{4}{12}

t=\frac{1}{3}\ hr

t=20\ min

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