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Ghella [55]
3 years ago
8

Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form

Mathematics
2 answers:
myrzilka [38]3 years ago
7 0

Answer:

y = 5x - 11

Step-by-step explanation:

1) Find slope

2) Substitute 1 point back into formula to find y-intercept, aka c

tresset_1 [31]3 years ago
7 0

ANSWER

y = 5x  - 11

EXPLANATION

The given line passes through:

(3,4) and (2,-1).

The slope is given by:

m =  \frac{ - 1 - 4}{2 - 3}

m =  \frac{ - 5}{ - 1}  =  5

The equation can be found using

y-y_1=m(x-x_1)

We plug in the point and slope to get:

y - 4 = 5(x - 3)

y - 4 = 5x  - 15

y = 5x  - 15 + 4

y = 5x  - 11

This is the slope-intercept form

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75 × 0.01 = 0.75

0.75 × 80 = $60

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8 0
3 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

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QveST [7]
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3 years ago
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Cameron buys 2.45 pounds of apples and 1.65 pounds of pears. Apples and pears each cost c dollars per pound. If the total cost a
nordsb [41]

Answer:

4.12=2.45c+1.65c

Step-by-step explanation:

We are given,

Cameron buys 2.45 pounds of apple and 1.65 pounds of pears.

Also, the cost of apples and pears is 'c' dollars per pound.

Thus, the cost of 2.45 pounds of apple is 2.45c dollars and the cost of 1.65 pounds of pear is 1.65c dollars.

Since, the total cost after using a coupon is $4.12.

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i.e. 4.12=4.1c

i.e. c=\frac{4.12}{4.1}

i.e. c = 1 dollar

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At Store A is the cost of apples the least. This is because it always has the lowest price for each pound compared to the other lines. Hope this helps!
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