Question

The Capulet and Montague families love writing. Last year, each Capulet wrote 4 essays, each Montague wrote 6 essays, and both families wrote 100 essays in total. This year, each Capulet wrote 8 essays, each Montague wrote 12 essays, and both families wrote 200 essays in total. How many Capulets and Montagues are there?

Answer 1

Answer:

Infinite solution

Step-by-step explanation:

Let, number of Capulet family = x and number of Montague family = y.

Since, last year, each Capulet wrote 4 essays and each Montague wrote 6 essays.

Moreover, total essays wrote last year are 100.

So, we get, 4x + 6y = 100.

Again, this year, each Capulet wrote 8 essays and each Montague wrote 12 essays.

Moreover, total essays wrote this year are 200.

So, we get, 8x + 12y = 200.

Thus, the system of equations is given by,

4x + 6y = 100.

8x + 12y = 200.

Dividing first equation by 2 and second equation by 4, we get the equation,

2x + 3y = 50.

Since, there is only one equation and two variables i.e. x and y.

There can be infinite number of possibilities for the values of x and y.

Answer 2

Answer:

Khan Academy says There is not enough information to determine the exact number of Capulets and Montagues

Step-by-step explanation:

Khan Academy saysss sooooo