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Pavlova-9 [17]
4 years ago
13

What is a supplementary angle

Mathematics
2 answers:
katrin [286]4 years ago
5 0

Answer:

A supplementary angle is two angles (or 2 right angles) that equals 180 degrees.

Step-by-step explanation:

Zigmanuir [339]4 years ago
5 0

Answer:

a supplementary angle is when two angles share the same vertex and when you add up both of their degrees it equals 180 degrees  

Step-by-step explanation:

say i have an angle on both sides and they share the same point. One side is 96 degrees and the other is 84. When you add them up it equals 180 degrees. This would be a supplementary angle.

A complementary angle would be the same thing but instead of it being 180 degrees, the sum would be 90 degrees. A good way to remember this is the C in complementary comes first in the alphabet so the lowest number is 90. And S in supplementary is farther than C so 180 Is larger than 90 .

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Only problem 6a. Can someone demonstrate how to do this so I can do the rest solo?
Lisa [10]

as far as I can tell, is simply asking to write two more expressions, that are equivalent to the provided one, namely, grab the provided one and expand it, if you simplify the expanded version, you'd end up with the provided, for example

\bf \boxed{6a.1}~\hfill  \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill  \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}}\\\\\\\boxed{6a.3}~\hfill \stackrel{ch anging}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

so let's do 6a1, 6a3 and 6a5.

\bf \boxed{6a.1}~\hfill \stackrel{changing}{\cfrac{29\cdot 3}{30\cdot 3}}\implies \stackrel{one}{\cfrac{87}{90}}~\hfill \stackrel{changing}{\cfrac{29\cdot 7}{30\cdot 7}}\implies \stackrel{t wo}{\cfrac{203}{210}} \\\\\\ \boxed{6a.3}~\hfill \stackrel{changing}{\cfrac{15\div 3}{30\div 3}}\implies \stackrel{one}{\cfrac{5}{10}}~\hfill \stackrel{changing}{\cfrac{15\div 5}{30\div 5}}\implies \stackrel{two}{\cfrac{3}{6}}

\bf \boxed{6a.5}~\hfill \stackrel{changing}{(9\cdot 10)\div (2\cdot 10)}\implies \stackrel{one}{90\div 20}~\hfill \stackrel{changing}{(9\cdot 70)\div(2\cdot 70)}\implies \stackrel{two}{630\div 140}

3 0
3 years ago
The sum of three consecutive integers is 267. What is the largest integer
zzz [600]
The 3 consecutive numbers are 88, 89, and 90. So 90 is the answer.
3 0
3 years ago
Read 2 more answers
Which table most accurately organizes the data from the graph?
Brilliant_brown [7]

Answer

It's B

Step-by-step explanation:

It organizes the years from 1-6 and keeps the money consistent with the years

5 0
2 years ago
0.3(4-x)=x-1.4 how do you solve this problem?
tresset_1 [31]

Answer:

x = 2.

Step-by-step explanation:

Solve for x:

0.3 (4 - x) = x - 1.4

Expand out terms of the left hand side:

1.2 - 0.3 x = x - 1.4

Subtract x from both sides:

1.2 + (-0.3 x - x) = (x - x) - 1.4

-0.3 x - x = -1.3 x:

-1.3 x + 1.2 = (x - x) - 1.4

x - x = 0:

1.2 - 1.3 x = -1.4

Subtract 1.2` from both sides:

(1.2 - 1.2) - 1.3 x = -1.2 - 1.4

1.2 - 1.2 = 0:

-1.3 x = -1.2 - 1.4

-1.2 - 1.4 = -2.6:

-1.3 x = -2.6

Divide both sides of -1.3 x = -2.6 by -1.3:

(-1.3 x)/(-1.3) = (-2.6)/(-1.3)

(-1.3)/(-1.3) = 1:

x = (-2.6)/(-1.3)

(-2.6)/(-1.3) = 2.:

Answer:  x = 2.

4 0
3 years ago
Civil an airport, a factory, and a shopping center are at the vertices of a right triangle formed by three highways. the airport
vekshin1

Answer:

<em>The shortest possible length for the service road is 2.88 miles.</em>

Step-by-step explanation:

According to the below diagram, A, B and C are the positions of airport, shopping center and factory respectively.

Given that,  AB= 3.6 miles, BC= 4.8 miles and AC= 6.0 miles

In right triangle ABC

tan(\angle ACB)=\frac{AB}{BC} \\ \\ tan(\angle ACB)= \frac{3.6}{4.8}=0.75\\ \\ \angle ACB= tan^-^1(0.75)=36.8698.... degree

The shortest possible length for the service road from the shopping center to the highway that connects the airport and factory is BD.

That means, \triangle BCD is also a right triangle in which \angle BDC=90\°, Hypotenuse(BC)= 4.8 miles and BD is the opposite side in respect of \angle DCB or \angle ACB.

Now in right triangle BCD

Sin(\angle ACB)=\frac{BD}{BC}\\ \\ Sin(36.8698...)=\frac{BD}{4.8}\\ \\ BD=4.8*Sin(36.8698...)=2.88

So, the shortest possible length for the service road is 2.88 miles.

4 0
4 years ago
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