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sleet_krkn [62]
3 years ago
12

How many positive 4-digit integers have only odd digits?

Mathematics
2 answers:
Sav [38]3 years ago
7 0
2,4,6,8 multiply by 3

12345 [234]3 years ago
6 0

Answer:

5^4 = 625

Step-by-step explanation:

There are 5 possible odd digits to choose from:  1,3,5,7,9.

When we chose our first digit, we have 5 choices (the possible odd digits). For every one of those 5 choices, we can chose our second digit in 5 different ways again, then we have 5*5 = 25 ways for choosing our first two digits. We can do the same again, as for every one of the 25 first two digits, we can chose our third digit in 5 different ways (again, the odd numbers). So we multiply it by 5 again. Repeating this one more time, because we have 5 different ways to chose our fourth digit. At the end we will have

5*5*5*5 = 5^4 = 625

This is a commun counting technique.

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Answer:

(2) 4, 7, 9; 2, 5, 6; 1, 3, 8

Step-by-step explanation:

Let's group them based on how many lines they have inside the shape...

0 lines: 4, 7, 9

2 lines: 2, 5, 6

3 lines: 1, 3, 8

Therefore the answer is (2) 4, 7, 9; 2, 5, 6; 1, 3, 8

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2 years ago
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3 years ago
Please solve...Thanks
liberstina [14]
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P=2l+2w
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