A sample of nitrogen gas has a pressure of 7.58 kPa at 639 K. What will be the pressure at 311 K if the volume does not change?
2 answers:
Answer: 3.69 kPa
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
(At constant volume and number of moles)
where,
= initial pressure of gas = 7.58 kPa
= final pressure of gas = ?
= initial temperature of gas = 639 K
= final temperature of gas = 311 K
Now put all the given values in the above equation, we get the final pressure of gas.
Therefore, the final pressure of gas will be 3.69 kPa.
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