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Serga [27]
3 years ago
12

A sample of nitrogen gas has a pressure of 7.58 kPa at 639 K. What will be the pressure at 311 K if the volume does not change?

Chemistry
2 answers:
omeli [17]3 years ago
7 0
Over here you have to use the formula: <span>P1/T1= P2/T2
P1= 7.58
T1= 639

P2= ?
T2= 311

</span><span>7.58/639 = ?/311
</span>= 3.689 kPa
melomori [17]3 years ago
6 0

Answer: 3.69 kPa

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas = 7.58 kPa

P_2 = final pressure of gas = ?

T_1 = initial temperature of gas = 639 K

T_2 = final temperature of gas = 311 K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{7.58 kPa}{639K}=\frac{P_2}{311K}

P_2=3.69kPa

Therefore, the final pressure of gas will be 3.69 kPa.

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