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Thepotemich [5.8K]
2 years ago
13

Why do you think nonmetals are used as insulators in thermos bottles?

Chemistry
1 answer:
Rama09 [41]2 years ago
4 0

Answer:

in non-metal elements the electrons are held much more tightly in the chemical bonds that hold the atoms together

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Word equation of nitrogen + oxygen —--> ammonia
katrin [286]

Answer:

it is ammonia nitro oxide

5 0
2 years ago
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Using the model of the periodic table, which two elements pictured have similar chemical properties?
Murljashka [212]

Answer:

1 and 3

Explanation:

The vertical columns (groups) of the periodic table are arranged such that all its elements have the same number of valence electrons. All elements within a certain group thus share similar properties.

5 0
3 years ago
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What occurs in order to break the bond in a Cl2 molecule?
alukav5142 [94]
The bond between the 2 Cl atoms in a Cl₂ molecule is a covalent bond. 
to break this covalent bond, energy is required. 
when new bonds form, energy is released as the bond formation makes the molecule stable. molecules with low energy levels are usually stable. 
To break the covalent bond, energy is required in other words energy is absorbed. 
therefore to break the covalent bond in Cl₂ molecule 
1)energy is absorbed
3 0
3 years ago
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A sample of gas contains 3.0L of nitrogen at 320kPa. What volume would be necessary to decrease the pressure at 110kPa
Phoenix [80]

Answer:

V_{2} = 8.92 L

Explanation:

We have the equation for ideal gas expressed as:

PV=nRT

Being:

P = Pressure

V = Volume

n = molar number

R = Universal gas constant

T = Temperature

From the statement of the problem I infer that we are looking to change the volume and the pressure, maintaining the temperature, so I can calculate the right side of the equation with the data of the initial condition of the gas:

P_{1} V_{1} =nRT

320Kpa*0.003m^{3} =nRT

1000L = 1m^{3}

So

nRT= 0.96

Now, as for the final condition:

P_{2}V_{2}=nRT

P_{2} V_{2} =0.96

clearingV_{2}

V_{2} =\frac{0.96}{P_{2} }

V_{2} =0.00872m_{3}

V_{2} = 8.92 L

6 0
3 years ago
You need to prepare 1 L of the citric acid/citrate buffer. You have chosen to use Method 1 (see lab presentation). Calculate the
prisoha [69]

Answer:

3.11 is the pH of the buffer

Explanation:

The pH of a buffer is obtained using H-H equation:

pH = pKa + log [Conjugate base] / [Weak acid]

<em>Where pH is the pH of the buffer, pKa = -log Ka = 3.14 for the citric buffer and [] could be taken as the moles of each species.</em>

The citric acid,HX (Weak acid), reacts with NaOH to produce sodium citrate, NaX (weak base) and water:

HX + NaOH → H2O + NaX

That means the moles of NaOH added = Moles of sodium citrate produced

And the resulitng moles of HX = Initial moles - Moles NaOH added

<em>Moles HX and NaX:</em>

Moles NaOH = 0.100L * (0.65mol / L) = 0.065 moles NaOH = Moles NaX

Moles HX = 0.300L * (0.45mol / L) = 0.135 moles HX - 0.065 moles NaOH = 0.070 moles HX

Replacing in H-H equation:

pH = 3.14 + log [0.065mol] / [0.070mol]

pH = 3.11 is the pH of the buffer

8 0
3 years ago
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