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solong [7]
3 years ago
12

The distance to the North Star, Polaris, is approximately 6.44 3 1018 m.

Physics
1 answer:
zhenek [66]3 years ago
8 0

Answer:

a) 2,042.1 years. b) 500 sec. c) 2.56 sec.

Explanation:

Visible light, is just an electromagnetic wave approximately within 400-700 nm) , so , in vacuum, propagates at a constant speed of 3. 10⁸ m/s.

So, in order to get the time needed for the light coming from any point of the universe can reach us, we just need to apply the velocity definition equation, as follows:

v = Δx / Δt, and solve for Δt, taking into account units.

a) if d = 6.44. 3.10¹⁸ m, and v = 3.10⁸ m/s, we find t as follows:

t = 6.44.3. 10¹⁸ / 3. 10⁸ s = 6.44 . 10¹⁰ sec.

Converting seconds to years:

6.44. 10¹⁰ sec . (1min/60 sec).(1h/60 min). (1d/24h)(1y/365d) = 2,042.1 years.

b) As the average distance earth-sun is 1.5.10⁸ m, we find t as follows:

t = 1.5 10¹¹ m / 3.10⁸ m/s = 500 sec = 8.33 min

c) As the average distance Earth-Moon is 3.84. 10⁸ m, we find t to be as follows:

t = 2. (3.84. 10⁸ m / 3. 10⁸ m/s) = 2.56 sec.

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Answer:

A.  when the mass has a displacement of zero

Explanation:

The velocity of a mass on a spring can be calculated by using the law of conservation of energy. In fact, the total energy of the mass-spring system is equal to the sum of the elastic potential energy (U) of the spring and the kinetic energy (K) of the mass:

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Since the total energy E must remain constant, we can notice the following:

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8 0
3 years ago
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A police car is located 50 feet to the side of a straight road. A red car is driving along the road in the direction of the poli
NNADVOKAT [17]

Answer:74.33 feet per sec

Explanation:

Given

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as the red car is moving

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\frac{\mathrm{d} x}{\mathrm{d} t}

2x\times \frac{\mathrm{d} x}{\mathrm{d} t}+0=2z\frac{\mathrm{d} z}{\mathrm{d} t}

x\frac{\mathrm{d} x}{\mathrm{d} t}=z\frac{\mathrm{d} z}{\mathrm{d} t}

140\times \frac{\mathrm{d} x}{\mathrm{d} t}=148.66\times 70

\frac{\mathrm{d} x}{\mathrm{d} t}=74.33 feet\ per\ sec

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Answer:

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