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GuDViN [60]
2 years ago
7

I don't hang out with girls so if you are a boy and you want to be friend say hi to me

Physics
2 answers:
ziro4ka [17]2 years ago
7 0
Wassup fam? How are you? I’m doing good, and I just wanna say..... nice question:D
MatroZZZ [7]2 years ago
4 0

Answer:

Uh No thanks but make me brainiest!

Explanation:

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HELP DUE TODAY BEST ANSWER GET BRAINLIE
Aleonysh [2.5K]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

3 0
3 years ago
A strong lightning bolt transfers about 25 C to earth. how many electrons are transferred?
Aneli [31]

Answer:

n = 1.563x {10}^{20}

8 0
2 years ago
Need help! Photo says all! Will mark brainliest :)
AVprozaik [17]

Answer:

C-D

Explanation:

As you can see from the graph, the distance from A to B was from 0 m to 6 m in a duration of 3 seconds.

Divide 6 meters by 3 seconds to find the speed:

6 ÷ 3 = 2 m/s

B-C is not moving due to a straight line as said in the graph, so speed is

0 m/s.

There is also C-D since the car traveled from a distance of 9 meters

(6 -(-3) = 9) in 3 seconds too. (NOTE: The graph line going down does not mean it is slowing down, but rather going to a certain distance like going backwards)

Divide 9 meters by 3 seconds to get the speed:

9 ÷ 3 = 3 m/s

Between A-B, B-C, and C-D, C-D has the fastest speed recorded with 3 m/s.

A-D does not count here as the line has no connection between point A and point D.

Cheers!

6 0
3 years ago
I REALLY NEED HELP ON THIS PLEASE HELP ME
Lapatulllka [165]

Answer:

I have no clue lol

Explanation:

8 0
2 years ago
Read 2 more answers
Ceres has an orbital semi-major axis = 2.768 AU. What is Ceres’ orbital period?
Doss [256]

Answer: 4.6 years

Explanation:

According to Kepler’s Third Law of Planetary motion <em>“The square of the orbital period T of a planet is proportional to the cube of the semi-major axis a (size) of its orbit”: </em>

<em />

T^{2}\propto a^{3} (1)  

However, if T is measured in Earth years, and a is measured in astronomical units (unit equivalent to the distance between the Sun and the Earth), equation (1) becomes:  

T^{2}=a^{3} (2)  

Knowing a=2.768 AU and isolating T from (2):  

T=\sqrt{a^{3}} (3)  

T=\sqrt{(2.768 AU)^{3}} (4)  

Finally:  

T=4.6 years This is Ceres' orbital period

6 0
3 years ago
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