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Anna11 [10]
2 years ago
11

Anyone know how to do this?

Physics
1 answer:
MrMuchimi2 years ago
7 0

The voltage from one side of the battery all the way around to the other side of the battery is 12v .

If 4 of those volts show up across the circle-thing, then the rest of the 12v ... 8v ... Must show up across the set of parallel rectangles.

To get that answer, I subtracted the 4 from the 12.

Just like it says in choice-C.

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In electroplating, the object to be plated is which part of an electrolytic cell? cathode or anode
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Since the anode dissolves and goes to the cathode. The object to be electroplated is kept at the cathode.

Please mark me as brainliest.

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3 years ago
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Technician A says that in a series circuit, if one light goes out, the rest of the lights stay on. Technician B says that in a p
vivado [14]

Answer:

Explanation:

Technician A is incorrect as in series circuit the current is the same for all the resistors and if one bulb fails in the path then the circuit is incomplete and therefore no flow of current.

Technician B is correct as in parallel circuit there are multiple paths for current through which it can pass and malfunctioning of one resistor does not affect the other.      

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3 years ago
A force of 1.5 × 102 N is exerted on a charge of 1.4 × 10–7 C that is traveling at an angle of 75° to a magnetic field.
Marysya12 [62]

Option (B) is correct.The magnetic field strength=8.5 x 10² T

Explanation:

the magnetic force Fm is given by

Fm= q V B sinθ

q= charge=1.4 x 10⁻⁷ C

v= velocity= 1.3 x 10⁶ m/s

B= magnetic field strength

Fm= magnetic force= 1.5 x 10² N

θ=75°

so 1.5 x 10²=(1.4 x 10⁻⁷) (1.3 x 10⁶ ) (B) sin75

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6 0
3 years ago
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Where is most of the mass of an atom located? in the nucleus in the orbits in the electrons it is split between the nucleus and
yulyashka [42]
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A submarine is stranded on the bottom of the ocean with its hatch 21.0 m below the surface. calculate the force (in n) needed to
Tanzania [10]

Answer:

28,400 N

Explanation:

Let's start by calculating the pressure that acts on the upper surface of the hatch. It is given by the sum of the atmospheric pressure and the pressure due to the columb of water, which is given by Stevin's law:

p_{top} = p_{atm} + \rho g h=1.013\cdot 10^5 Pa + (1000 kg/m^3)(9.8 m/s^2)(21.0 m)=3.071 \cdot 10^5 Pa

On the lower part of the hatch, there is a pressure equal to

p_{bot}=p_{atm}=1.013\cdot 10^5 Pa

So, the net pressure acting on the hatch is

p=p_{top}-p_{bot}=3.071 \cdot 10^5 Pa - 1.013\cdot 10^5 Pa=2.058 \cdot 10^5 Pa

which acts from above.

The area of the hatch is given by:

A=\pi r^2 = \pi (\frac{0.420 m}{2})^2=0.138 m^2

So, the force needed to open the hatch from the inside is equal to the pressure multiplied by the area of the hatch:

F=pA=(2.058\cdot 10^5 Pa)(0.138 m^2)=28,400 N

8 0
3 years ago
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