Answer:
Explanation:
From Kinetic energy K.E = m*/2
Where mass of the car, m = 850 kg
velocity of the car, v = 18 m/s
Hence K.E =
Also, we can evaluate the given time
time = K.E / Power
=
= 2.87 secs
Answer:
the average force exerted by seatbelts on the passenger is 5625 N.
Explanation:
Given;
initial velocity of the car, u = 50 m/s
distance traveled by the car, s = 20 m
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 90 kg
Determine the acceleration of the car as it hit the pile of dirt;
v² = u² + 2as
0 = 50² + (2 x 20)a
0 = 2500 + 40a
40a = -2500
a = -2500/40
a = -62.5 m/s²
The deceleration of the car is 62.5 m/s²
The force exerted on the passenger by the backward action of the car is calculated as follows;
F = ma
F = 90 x 62.5
F = 5625 N
Therefore, the average force exerted by seatbelts on the passenger is 5625 N.
That makes no sense I can't help sorry
If the volume is the same and the temperature increases, then the molecules will move around faster and bump more against the balloon, so the pressure will increase.