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lesya692 [45]
2 years ago
7

The measured value of mass M in an experiment is M = 0.743 ± 0.005kg. The error in 2M is

Physics
1 answer:
omeli [17]2 years ago
8 0

Given the measured value of mass M in the experiment the error in 2M is  ; dM

<u>Given data :</u>

Measured value of mass M = ( 0.743 ± 0.005 ) kg

<h3>The error in 2M in the measured value </h3>

The error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM

Hence we can conclude that the measured value of mass M in the experiment the error in 2M is  ; dM.

Learn more about error in 2M : brainly.com/question/6650225

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An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum
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The pressure is  P_2  =  4.25 \ a.t.m

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From the question we are told that

   The initial pressure is P_1  =  11.2\ a.t.m

   The  temperature is  T_1 =   299 \ K

   

Let the first volume be  V_1 Then the final volume will be  2 V_1

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Here r is the radius of the molecules which is  mathematically represented as

    r =  \frac{C_p}{C_v}

Where C_p \  and\   C_v are the molar specific heat of a gas at constant pressure and  the molar specific heat of a gas at constant volume with values

     C_p=7 \  and\   C_v=5

=>   r =  \frac{7}{5}

=>  11.2*( V_1 ^{\frac{7}{5} } ) =  P_2  *  (2 V_1 ^{\frac{7}{5} } )

=>   P_2  =  [\frac{1}{2} ]^{\frac{7}{5} } * 11.2

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