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Dahasolnce [82]
3 years ago
13

A local elevator moves upward at a constant 2.1 mps passing a stopped express elevator. Precisely 2.7 seconds later the express

elevator catches up with the local elevator where the velocity of the local with respect to the express elevator is -9.5 m/s. Determine (a) the acceleration of the express elevator in m/s/s he distance traveled in m for the
Physics
1 answer:
adoni [48]3 years ago
6 0

Answer:

4.3 m/s² ( approx )

Explanation:

Velocity of local elevator with respect to express elevator initially is 2.1 mps

After 2.7 seconds , the gap between them is

2.7 x 2.1 = 5.67 m

The express elevator begins with acceleration . At the time of catching up

velocity of local with respect to express is - 9.5 m /s .That means velocity of

express with respect to local will be 9.5 m/s .

Relative velocity of express is 9.5 m/s

Absolute velocity of express is 9.5 + 2.1 = 11.6 m/s

Acceleration of express = change in velocity / time

= ( 11.6 -0)/ 2.7 = 4.3 m/s² ( approx )

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11111nata11111 [884]

Explanation:

Given that,

A student travels 11 m north and then turns around to travel 25 m south.

Total time, t = 12 s

The total distance or the total path covered by the student is equal to 11 m + 25 m = 36 m

Displacement of the student or the shortest path covered is d = 25-11 = 14 m

(a) The student's average speed = total distance/total time

s=\dfrac{36\ m}{12\ s}\\\\s=3\ m/s

(b) The student's average velocity = total displacement/total time

v=\dfrac{14\ m}{12\ s}\\\\v=1.17\ m/s

4 0
3 years ago
Which of the following is a correct step in the process of adding 8.0 x 10^ -2 and 6.0 x 10^ -3
dybincka [34]

Explanation:

In order to compute correctly the sum of the two terms, we have to rewrite one of them such that they have the same exponent.

The two terms are:

8.0 \cdot 10^{-2}

6.0 \cdot 10^{-3}

For instance, we can re-write the second term such as it also has a power 10^{-2}. In order to do that, we have to move the decimal point one place to the left, therefore:

6.0 \cdot 10^{-3} = 0.6\cdot 10^{-2}

At this point, the two numbers have the same exponent, so we can just add them together by adding the bases and keeping the same exponent, -2:

8.0\cdot 10^{-2} + 0.6 \cdot 10^{-2} = (8.0 + 0.6) \cdot 10^{-2} = 8.6\cdot 10^{-2}

8 0
4 years ago
An elevator has the mass of 3 tons of power needed to raise the elevator 50m in 15 s?PLEASE HELP PLEASE IM SCARED
madreJ [45]

Answer:

Time=15,Mass=3,Acceleration due to gravity=10,Height=50,Power=?.

Power=mgh/t.....which is 3×10×50=1500/15=100Watts.

8 0
3 years ago
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Which energy does the water flow into the river?
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The water in a reservoir behind a hydropower dam is another example of potential energy. The stored energy in the reservoir is converted into kinetic energy (motion) as the water flows down a large pipe called a penstock and spins a turbine.
6 0
4 years ago
Thomas threw a ball down a pit that was 400m deep. a) How long did it take to land? b) What speed was it going when it landed?​
bulgar [2K]

Hi there!

a)

We can use the equation t = √2d/g to solve. (Let's let g = 10 m/s²)

**How to get this equation**

We have the equation:

Δd = vit + 1/2at²

For freefall, we know that vi = 0, so we are left with:

Δd = 1/2at²

We know that a = g. Rearrange in terms of t:

2Δd / a = t²

Square root both sides:

√(2d/a) = t

Plug in the height and gravity:

t = √2(400)/10 = √800/10 = √80 ≈ 8.94 sec

b)

Find the final speed using the following formula:

vf = √2gd

**How to derive**

We know the equation:

vf² = vi² + 2ad

vi = 0, so:

vf² = 2ad

Square root both sides:

vf = √2ad

vf = √2(400)(10) = √8000 ≈ 89.44 m/s

6 0
3 years ago
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