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3 years ago

What transplant method would prevent the rejection of tissue after an organ transplant

1 answer:

4 0

Using organs cloned from the cells of the patient <span>would prevent the rejection of tissue after an organ transplant.</span>

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Learning Goal: To practice Problem-Solving Strategy 30.1 Electromagnetic Induction. A coil of wire contains N turns and has an e

Helen [10]

Answer:

Time interval for which magnetic field reduced to ZERO is given as

$t = \frac{NB_0\pi a^2}{RI}$

Explanation:

As we know that the flux linked with one coil is given as

$\phi = B_0 A$

$\phi = B_0(\pi a^2)$

now total flux of all coils is given as

$\phi = NB_0\pi a^2$

now let say the flux is reduced to ZERO after time "t"

so as per Faraday's law EMF induced in the coil is given as

$EMF = \frac{NB_0\pi a^2 - 0}{t}$

now the current in the coil is given as

$I = \frac{EMF}{R}$

$I = \frac{NB_0\pi a^2}{Rt}$

so the time interval is given as

$t = \frac{NB_0\pi a^2}{RI}$

8 0

3 years ago

Minerals that form from magma process will tend to form ?

NISA [10]

igneous rocks, and can either be entrusive or extrusive.

3 0

2 years ago

Please expert solve this

777dan777 [17]

Explanation:

I am not expect I am ambitious

5 0

2 years ago

PLZ HELP I DONT GET IT

GaryK [48]

Answer:

0.1 L

Explanation:

From the question given above, we obtained the following data:

Initial volume (V₁) = 0.05 L

Initial Pressure (P₁) = 207 KPa

Final pressure (P₂) = 101 KPa

Final volume (V₂) =?

We can obtain the new volume (i.e the final volume) of the gas by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

207 × 0.05 = 101 × V₂

10.35 = 101 × V₂

Divide both side by 101

V₂ = 10.35 / 101

V₂ = 0.1 L

Thus, the new volume of the gas is 0.1 L

6 0

2 years ago

Consider a thin circular disk that has been heated up to 400 °C and then left inside a chamber to cool down. The chamber surface

kogti [31]

Answer:

hello your question lacks the required diagram attached below is the complete question with the required diagram

answer : Qtotal = 807.4 Mw

Explanation:

Given Data :

disk properties :

∈ = 0.65

D = 200 mm

Ts = 400⁰c

attached below is the detailed solution

The total rate of Heat transferred from the disk

Qtotal = 807.4 Mw

7 0

3 years ago