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3 years ago

What transplant method would prevent the rejection of tissue after an organ transplant

1 answer:

4 0

Using organs cloned from the cells of the patient would prevent the rejection of tissue after an organ transplant.

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An object attached to a horizontal spring is oscillating back and forth along a frictionless surface. the maximum speed of the o

Andreas93 [3]

First of all, the maximum speed occurs when the object passes through the
equilibrium position

The kinetic energy when the object has this max speed is

K= 1/2 * mass * (1.25 m/s)^2

The potential energy in the spring when the speed is equal to zero

U= 1/2 * k * xmax^2

The maximun force of the spring is

mass*acceleration = k*xmax

m * 6.89 m/s2 = k * xmax
xmax = 6.89* m / k

0.5 * m * 1.56 = 0.5 * k * xmax^2

m * 1.56 = k * (6.89* m / k )^2 

1.56 m = 47.47 m^2 / k
m/k = 0.032862

period = 2 *pi*sqrt[m/k]
= 2 pi sqrt [ 0.032862]
= 1.139 s

A fourth of the period elapses between the instants of max acceleration and maximum speed

= 1/4* period
= 1/4 * 1.139 s = 0.284s

7 0

4 years ago

Unpolarized light with an average intensity of 845 W/m2 enters a polarizer with a vertical transmission axis. The transmitted li

RideAnS [48]

The concept to develop this problem is the Law of Malus. Which describes what happens with the light intensity once it passes through a polarized material.

Mathematically this can be expressed as

$I = I_0 cos^2\theta$

Where

I = New intensity after pass through the Polarizer

$I_0$ = Original intensity

$\theta$ = Indicates the angle between the axis of the analyzer and the polarization axis of the incident light.

When the light passes perpendicularly through the first polarizer, the light intensity is reduced by half which will cause the intensity to be $225W / m ^ 2$ at the output of the new polarizer, mathematically:

$I= \frac{I_0}{2} cos^2\theta$

$225 = \frac{845}{2}cos^2\theta$

Solving to find the angle we have

$\theta = 43.11\°$

The orientation angle of the second polarizer relative to the first one is 43.11°

5 0

3 years ago

A circular grill of diameter 0.25 m has an emissivity of 0.8. If the surface temperature is maintained at 150°C, determine the r

Schach [20]

Answer:

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

Explanation:

Power required to maintain the surface temperature at 150°C from 20°C

P= εσA(T^4-t^4)

P= power in watt

ε= emissivity

A= area of surface

T= 150°C= 423 K

t= 20°C= 303K

/sigma= 5.67×10^{-8} watt/m^2K^4

putting vales we get

$= 0.8\times5.67\times10^{-8} \pi\frac{0.25^4}{4}(423^4-303^4)$

P=52.51822 Watt

the required electrical power when the room air and surroundings are at 30°C.= 52.51822 Watt

4 0

3 years ago

After an afternoon party, a small cooler full of ice is dumped onto the hot ground and melts. If the cooler contained 5.50 kg of

zysi [14]

Answer:

$Q = 4.40 \times 10^5 Cal$

Explanation:

Here we know that initial temperature of ice is given as

$T = 0^o C$

now the latent heat of ice is given as

$L = 80 Cal/g$

now we also know that the mass of ice is

$m = 5.50 kg$

so here we know that heat required to change the phase of the ice is given as

$Q = mL$

$Q = (5.50 \times 10^3)(80)$

$Q = 4.40 \times 10^5 Cal$

3 0

3 years ago

An endothermic reaction will start when the required ΔH energy is received from the environment or solution. True or False.

34kurt

An endothermic reaction will start when the required ΔH energy is received from the environment or solution this is false as the reaction may require energy in excess to start the reaction

5 0

3 years ago

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