The standard equation is 4p(x-h) = (y-k)^2 where |p| = focal distance |4p| = focal width.
<span>x=-1/8y^2
-8x=y^2
4*(-2)(x-0) =( y-0)^2
p = -2, h=0, k=0</span><span>
focal width = |4*(-2)| = 8
The answer to your question is that the length of the focal width is equal to 8.</span>
Answer:
29.5+/-1.11
= ( 28.39, 30.61)
Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 29.5
Standard deviation r = 5.2
Number of samples n = 59
Confidence interval = 90%
z-value (at 90% confidence) = 1.645
Substituting the values we have;
29.5+/-1.645(5.2/√59)
29.5+/-1.645(0.676982337100)
29.5+/-1.113635944529
29.5+/-1.11
= ( 28.39, 30.61)
Therefore, the 90% confidence interval (a,b) =( 28.39, 30.61)
Answer:
It would be very difficult to determine the area without any given measurements of the sides. I'm afraid I cannot help you with this question.
Step-by-step explanation:
162 - 9 = 153.
d = 153.
Diego is old.
Their is not a lot of information but I think it is 12*24=288
