To solve the problem shown above you must keep on mind the following information given in the problem:
1. You have that <span>A reflection pool 27 meters long measured 1.8 centimeters on the drawing. Therefore, you can calculate the scale drawing of the city park as below:
</span>
scale=1.8/27
scale=1/15
2. Therefore, as you can see, the answer is:
The scale used to make the drawing is 1:15 (This means that 1 centimeter represents 15 meters).
Answer:
PT = 1.5 , VT = 1.5√3
Step-by-step explanation:
Given
PV = 3
With reference angle 60°
hypotenuse (h) = 3
perpendicular (p) = ?
sin 60° = p/h
√3 / 2 = p / 3
p = √3 * 3 / 2
p = 1.5√3
With reference angle 30°
hypotenuse (h) = 3
perpendicular (p) = ?
sin 30° = p/h
1/2 = p/ 3
p = 1.5
Hope it will help :)❤
Answer:
The sum of two numbers is 18.
5 times the first number subtracted from 4/7 of the second number is 14.
First number --> x
Second number --> y
so
x + y = 18 --> x = 18-y
5x - (4/7)y = 14
so
5 (18-y) - (4/7)y = 14
90 - 5y - 4/7 y = 14
-5.57 y = 14-90
y = 13.64
so
x = 18 - 13.64
x = 4.36
First of all, you surely do have a lot of incorrect grammar in your statement. I can't understand a word that you are asking.
(i) The area of the cross section ABCDEFG is 1771.6cm³
(ii) The volume of the concrete lab is 212592 cm³
(iii) the total surface area of the concrete slab is 30284 cm²
(iv) The mass of the concrete slab is 40746.8 kg/m³.
Given, dimensions are 120 cm by 60 cm by
40 cm.
(i) area of cross section = 40 × 60 ₋ π(60 ₋10 ₋ 10)/2 . 1/2
= 1771.6 cm³
(ii) the volume of the concrete slab = 40 × 60 × 120 ₋ 1/2 π((60 ₋ 10 ₋10)/2)² . 120
= 212592 cm³
(iii) The total surface area is:
=40 × 120 × 2 ₊ 60 × 120 ₊ 1771.6 × 2 ₊ 10 × 120 × 2 ₊ 1/2 π(60 ₋ 10 ₋10) × 120
= 30284 cm²
(iv) Mass of the concrete slab given density is 2300 kg/m³
Mass = Volume × density
Mass = 17.716 m³ × 2300
= 40746.8 kg/m³
Hence we get the mass as 40746.8 kg/m³.
Learn more about "Mensuration" here-
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