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faltersainse [42]
3 years ago
13

in 1984 don, disk that stayed aloft for 16.7 seonds supsuppose cain ran up a staricase during this time, reachig a height of 18.

4 m if his mass was 72 kg how much powerwas needed for his ascent
Physics
1 answer:
laila [671]3 years ago
8 0

Answer

given,

time of disk stayed a loft = 16.7 sec

height reached = 18.4 m

mass  = 72 kg

now work done is equal to change in potential energy

W = - (U_f - U_i)

W = - (mgh - 0)

W = - (72\times (-9.8) \times 18.4)

W = 12983.04 J

Positive sign means that work is in the direction of motion.

Power = \dfrac{Work\ done}{time}

Power = \dfrac{W}{t}

Power = \dfrac{12983.04}{16.7}

P = 777.42 Watts

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3 years ago
A satellite is orbiting earth at a distance of 35.0 kilometers. The satellite has a mass of 500 kilograms. What is the force bet
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Answer:

F = 4856.32 N

Explanation:

Given,

A satellite is orbiting earth at a distance from Earth surface, h = 35000 m

The mass of the satellite, m = 500 Kg

The radius of the Earth, R = 6.371 x 10⁶ m

The mass of the Earth, M = 5.972 x 10²⁴ Kg

The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²

The force between the Earth and the satellite is given by the formula

                                    F = GMm/(R+h)²  N

Substituting the values in the above equation

        F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²

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Hence,  the force between the planet and the satellite is, F = 4856.32 N

5 0
3 years ago
A football player runs directly down the field for 45m before turning to the right at an angle of 25 degrees from his original d
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You ride your bike from home to school, covering a distance of 3 km in 15 min. what is your average speed in km/h?
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3 years ago
A very light ideal spring having a spring constant (force constant) of 8.2 N/cm is used to lift a 2.2-kg tool with an upward acc
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Answer:

x = 3.5 cm

Explanation:

When spring is used as a lift tool

so the mass suspended on it will have spring force on it

So as per the force equation of mass we can say

F_{net} = ma

now net force on the mass is

F_{net} = kx - mg

F_{net} = kx - mg = ma

here we have

kx = mg + ma

now we have

x = \frac{mg + ma}{k}

x = \frac{2.2(9.8) + 2.2(3.25)}{8.2}

x = 3.5 cm

6 0
4 years ago
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