Answer:
The first one is graph and the second one is electronic balance, third computer then data table and the last is graduated cylinder.
Explanation:
cuz i got it right
Which were difficulties that the builders of the transcontinental railroad found ways to overcome? Select all the choices that apply.
Answer: Out of all the options presented above the ones that represent the difficulties that the builders of the transcontinental railroad found ways to overcome are answer choices A) providing supplies to build the tracks and support the workers and B) natural barriers such as mountains, rivers, and forests. It was also the same reason why the transcontinental railroad was being constructed. It would help the transportation of if this is hitory i dont know what subject this is but if its history heres the answers
Answer:
9.81 × 10⁻¹⁰ C
Explanation:
Given:
Distance between the tissue and the tip of the scale, r = 6 cm = 0.06 m
Charge on the ruler, Q = - 12 μC = - 12 × 10⁻⁶ C
Mass of the tissue = 3 g = 0.003 Kg
Now,
The force required to pick the tissue, F = mg
where, g is the acceleration due to gravity
also,
The force between (F) the charges is given as:
where,
q is the charge on the tissue
k is the Coulomb's constant = 9 × 10⁹ Nm²/C²
thus,
on substituting the respective values, we get
or
q = 9.81 × 10⁻¹⁰ C
Minimum charge required to pick the tissue paper is 9.81 × 10⁻¹⁰ C
Answer:
s = mV/2b
Assumptions: 1. the darts finally velocity is zero
2. The force being exerted on the dart by the block is constant and so the dart moves through the block with constant acceleration in the opposite direction. (Newton's second law)
3. Since the acceleration of the dart through the block is constant, then the equations of constant acceleration motion apply to the motion of the dart through the block.
Explanation:
Let a = acceleration of the dart through the block
V = velocity of the dart
m = mass of the dart
Vf = finally velocity of the dart
S = distance traveled by the dart through the block.
From Newton's second law of motion which states that the acceleration of a body is in the same direction as the net force acting on the body and is equal to the force divided by the mass. That is F = ma
Also F = -bv ........(1)
Therefore -bv = ma........(2)
From the equals of constant acceleration motion, Vf² = V² + 2aS
Vf = 0
0² = V² + 2aS
-2aS = V²
a = -V² / 2S
Substituting this expression for a in
Equation (2) above
-bV = m( - V²/2S)
On rearranging,
S = mV/2b
