Question

A very light ideal spring having a spring constant (force constant) of 8.2 N/cm is used to lift a 2.2-kg tool with an upward acceleration of 3.25 m/s2. If the spring has negligible length when it us not stretched, how long is it while it is pulling the tool upward?

Answer 1

Answer:

x = 3.5 cm

Explanation:

When spring is used as a lift tool

so the mass suspended on it will have spring force on it

So as per the force equation of mass we can say

$F_{net} = ma$

now net force on the mass is

$F_{net} = kx - mg$

$F_{net} = kx - mg = ma$

here we have

$kx = mg + ma$

now we have

$x = \frac{mg + ma}{k}$

$x = \frac{2.2(9.8) + 2.2(3.25)}{8.2}$

$x = 3.5 cm$