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kicyunya [14]
3 years ago
12

Construct the Tukey 95% confidence intervals to isolate the pairs of means contributing to the overall difference. For each pair

indicate whether the two means are different or not. Hint: Work on submitting three trials for the Tukey paramter and the standard error first. If you do not get them in three trials, continue submitting up to three trials for each of the confidence intervals until you get one correct. Then go back and submit the fourth trial for the previous parts. Do not submit the one trial for the significance until the interval is correct.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

Please see attachment

Step-by-step explanation:

Please see attachment

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Simplify (tan(θ)+cot(θ))/(sec(θ)•csc(θ)) completely
AlekseyPX
\dfrac{\tan\theta+\cot\theta}{\sec\theta\csc\theta}=\dfrac{\dfrac{\sin\theta}{\cos\theta}+\dfrac{\cos\theta}{\sin\theta}}{\dfrac1{\cos\theta}\dfrac1{\sin\theta}}=\dfrac{\sin^2\theta+\cos^2\theta}1=1
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What are prime numbers ? And a list of examples ?
Helga [31]

Answer:

the number which is divisible only by itself and 1 is called prime number. For example; 2,3, 5, 7, 11 and others.

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What graph shows the system of linear equations for which (-3/2,0) is a solution
Tamiku [17]

Answer:

See description.

Step-by-step explanation:

Any graph where the two lines intersect at (-3/2, 0) will be the correct graph.

Here is an attached example.

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3 years ago
A jewelry store purchases necklaces for n dollars each. The necklaces are then marked up by 20%, and costumers are charged 5% sa
Aleksandr [31]

Answer:

Step-by-step explanation:

Cost price = $n

Mark up price = selling price- cost price

= (20% × $n)

Selling price = $n + (20% × $n)

Sales tax = 5% × ($n + (20% × $n))

Total cost = selling price + sales tax

Total cost = $n + (20% × $n) + 5% × $n + (20% × $n)

= 1.2 × $n + 0.06 × $n

= 1.26 × $n.

8 0
3 years ago
Find the area between y = 8 sin ( x ) y=8sin⁡(x) and y = 8 cos ( x ) y=8cos⁡(x) over the interval [ 0 , π ] . [0,π]. (Use decima
Marina86 [1]

Answer:

0.416 au

Step-by-step explanation:

Let y1=8sin(x) and y2=8cos(x), we must find the area between y1 and y2

\int\limits^\pi _0{(8cos(x)-8sin(x))} \, dx = 8\int\limits^\pi _0{(cos(x)-sin(x))} \, dx =\\8(sin(x)+cos(x)) evaluated(0-\pi )=\\8(sin(\pi )-sin(0))+8(cos(\pi )-cos(0))=\\8(0.054-0)+8(0.998-1)=8(0.054)+8(-0.002)=0.432-0.016=0.416

3 0
3 years ago
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