Answer:
The first minimum would be observed at 41.57°
Explanation:
v = 340m/s = speed of sound
f = 610Hz
d = 0.840m
λ = ?
Mλ = wsinθ
m = mth order minima
λ = wavelength incident on the single slit
θ = angular position of the mth minima
But, λ = v / f
λ = 340 / 610 = 0.557m
θ = sin⁻(mλ/d)
θ = sin⁻ [(1 * 0.557) / 0.840]
θ = sin⁻ 0.6635
θ = 41.57°
The first minimum would be observed at 41.57°
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Answer:
Explanation:
m₂ is hanging vertically and m₁ is placed on inclined plane . Both are in limiting equilibrium so on m₁ , limiting friction will act in upward direction as it will tend to slip in downward direct . Tension in cord connecting the masses be T .
For equilibrium of m₁
m₁ g sinα= T + f where f is force of friction
m₁ g sinα= T + μsx m₁ g cosα
m₁ g sinα - μs x m₁ g cosα = T
For equilibrium of m₂
T = m₂g
Putting this value in equation above
m₁ g sinα - μs x m₁ g cosα = m₂g
m₂ = m₁ sinα - μs x m₁ cosα