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PSYCHO15rus [73]
3 years ago
7

A certain battery can power a 100 ohm-resistance device for 4 hours. how long can the battery power a 200 ohm device?

Physics
1 answer:
zimovet [89]3 years ago
3 0
Too easy:


100Ω/4 sec = 200Ω/t

t= 8 sec

and physics and physics and physics and physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physicsand physics



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Ymorist [56]

Answer:440.03 N

Explanation:

Given

horizontal component of acceleration (a_x)=800 m/s^2

vertical component of acceleration (a_y)=880 m/s^2

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Force in vertical direction =m\times a_y=0.37\times 880=325.6 N

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A soccer ball collides with another soccer ball at rest. the total momentum of the balls
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3 years ago
A −4.00 μC charge sits in static equilibrium in the center of a conducting spherical shell that has an inner radius 3.13 cm and
Mariulka [41]

Answer:

(a). The charge on the outer surface is −2.43 μC.

(b). The charge on the inner surface is 4.00 μC.

(c). The electric field outside the shell is 3.39\times10^{7}\ N/C

Explanation:

Given that,

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q=-6.43+2.43= 4.00\ \mu C

We need to calculate the electric field outside the shell

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E=\dfrac{kq}{r^2}

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E=\dfrac{9\times10^{9}\times6.43\times10^{-6}}{(4.13\times10^{-2})^2}

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(b). The charge on the inner surface is 4.00 μC.

(c). The electric field outside the shell is 3.39\times10^{7}\ N/C

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3 years ago
A procedure called______is used to find the volume of a rock
KengaRu [80]

Displacement is usually how the messure the rock

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