The first step that Enrique must take in order to calculate the tangential speed of the satellite is to convert the period from days to seconds.
We know that the SI unit of speed is meter per second and now, we with to obtain the tangential speed of the satellite.
Since the period is given in days, the first step is to convert the period from days to seconds.
Learn more: brainly.com/question/17638582
Answer:
Negative 3
Explanation:
Bc scientific notation is the zeros either ahead or behind the actual numbers
A free market economy<span> has two key </span>advantages<span>. First, it allows for individuals to innovate. Individuals have the freedom to create new ideas, new products, and new services to sell for profit. They are not required to only produce what the government tells them to produce.</span>
According to the Law of Conservation of Energy, energy is neither created nor destroyed. They are just transferred from one system to another. To obey this law, the energy of the substances inside the container must be equal to the substance added to it. The energy is in the form of heat. There can be two types of heat energy: latent heat and sensible heat. Sensible heat is energy added or removed when a substance changes in temperature. Latent heat is the energy added or removed at a constant temperature during a phase change. Since there is no mention of phase change, we assume the heat involved here is sensible heat. The equation for sensible heat is:
H = mCpΔT
where
m is the mass of the substance
Cp is the specific heat of a certain type of material or substance
ΔT is the change in temperature.
So the law of conservation of heat tells that:
Sensible heat of Z + Sensible heat of container = Sensible heat of X
Since we have no idea what these substances are, there is no way of knowing the Cp. We can't proceed with the calculations. So, we can only assume that in the duration of 15 minutes, the whole system achieves equilibrium. Therefore, the equilibrium temperature of the system is equal to 32°C. The answer is C.
Answer:
The “terminal speed” of the ball bearing is 5.609 m/s
Explanation:
Radius of the steel ball R = 2.40 mm
Viscosity of honey η = 6.0 Pa/s
![\text { Viscosity has Density } \sigma=1360 \mathrm{kg} / \mathrm{m}^{3}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Viscosity%20has%20Density%20%7D%20%5Csigma%3D1360%20%5Cmathrm%7Bkg%7D%20%2F%20%5Cmathrm%7Bm%7D%5E%7B3%7D)
![\text { Steel has a density } \rho=7800 \mathrm{kg} / \mathrm{m}^{3}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Steel%20has%20a%20density%20%7D%20%5Crho%3D7800%20%5Cmathrm%7Bkg%7D%20%2F%20%5Cmathrm%7Bm%7D%5E%7B3%7D)
![\left.\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2} \text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }\right)](https://tex.z-dn.net/?f=%5Cleft.%5Cmathrm%7Bg%7D%3D9.8%20%5Cmathrm%7Bm%7D%20%2F%20%5Cmathrm%7Bs%7D%5E%7B2%7D%20%5Ctext%20%7B%20%28g%20is%20referred%20to%20as%20the%20acceleration%20of%20gravity.%20Its%20value%20is%20%7D%209.8%20%5Cmathrm%7Bm%7D%20%2F%20%5Cmathrm%7Bs%7D%5E%7B2%7D%20%5Ctext%20%7B%20on%20Earth%20%7D%5Cright%29)
While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)
![V_{t}=\frac{2 \mathrm{R}^{2}(\rho-\sigma) \mathrm{g}}{9 \eta}](https://tex.z-dn.net/?f=V_%7Bt%7D%3D%5Cfrac%7B2%20%5Cmathrm%7BR%7D%5E%7B2%7D%28%5Crho-%5Csigma%29%20%5Cmathrm%7Bg%7D%7D%7B9%20%5Ceta%7D)
Substitute the given values to find "terminal speed"
![\mathrm{V}_{\mathrm{t}}=\frac{2 \times 0.0024^{2}(7800-1360) 9.8}{9 \times 6}](https://tex.z-dn.net/?f=%5Cmathrm%7BV%7D_%7B%5Cmathrm%7Bt%7D%7D%3D%5Cfrac%7B2%20%5Ctimes%200.0024%5E%7B2%7D%287800-1360%29%209.8%7D%7B9%20%5Ctimes%206%7D)
![\mathrm{V}_{\mathrm{t}}=\frac{0.0048 \times 6440 \times 9.8}{54}](https://tex.z-dn.net/?f=%5Cmathrm%7BV%7D_%7B%5Cmathrm%7Bt%7D%7D%3D%5Cfrac%7B0.0048%20%5Ctimes%206440%20%5Ctimes%209.8%7D%7B54%7D)
![\mathrm{V}_{\mathrm{t}}=\frac{302.9376}{54}](https://tex.z-dn.net/?f=%5Cmathrm%7BV%7D_%7B%5Cmathrm%7Bt%7D%7D%3D%5Cfrac%7B302.9376%7D%7B54%7D)
![\mathrm{V}_{\mathrm{t}}=5.609 \mathrm{m} / \mathrm{s}](https://tex.z-dn.net/?f=%5Cmathrm%7BV%7D_%7B%5Cmathrm%7Bt%7D%7D%3D5.609%20%5Cmathrm%7Bm%7D%20%2F%20%5Cmathrm%7Bs%7D)
The “terminal speed” of the ball bearing is 5.609 m/s