Answer: The same current flows through bth cables
Explanation:
Lets have a look to the next two equations
The Ohm´s V = I*R (1)
where:
V is voltage (potencial dfference) in volts
I is the electric current in ampers
R is the electric resistance
When a voltage is applied as the electrc load is not specified ( we have to assume is the same) the current will be the same
And in the other hand the resistance R =ρL/s
Where ρ is the resistivity of the conductor L the length and s square section of the conductor
If we assume that the smaller diameter cable is able to conduct the current then nothing happens. The point is that the capacity of conduction of current depend on the section of the cable (the area)
Tables exist where to find the capacity of each cable according to its diameter.
Answer:
Motion with constant velocity of magnitude 1 m/s (uniform motion) for 4 seconds in a positive direction and then for 2 seconds uniform motion with constant velocity of magnitude 3 m/s in reverse direction .
Explanation:
The graph shows a constant velocity of 1 m/s for 4 seconds in the positive direction. After that, between 4 seconds and 6 seconds, the object reverses its motion with constant velocity of magnitude 3m/s.
Answer:
C. Newton's First Law of Motion
Explanation:
As the car comes to an abrupt stop, the body is still moving forward, and is moved back by the seatbelt, an outside force. If not for the seatbelt, the body would continue forward until acted on by the car itself, or thrown out of the car.
The work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
<h3>
Work done by a single force on the chandelier</h3>
The work done by a single force on the chandelier is determined by taking the net horizontal force applied on the chandelier over the given distance.
where;
is frictional force = 0 (smooth surface).
<h3>Work done by the two forces</h3>
When the two forces combine to pull the chandelier, the total work done will be shared by the two forces.
Thus, the work done by the two forces in moving the chandelier to the given distance is 5,091.2 J.
Learn more about work done here: brainly.com/question/8119756