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mote1985 [20]
3 years ago
11

What is it called cavity left behind in the rock after an organism's hard part has dissolved.

Physics
1 answer:
Lapatulllka [165]3 years ago
5 0

Mold

Explanation:

A mold is a cavity that is left behind in the rock after an organism hard part has been dissolved. These are important fossils that useful in relative dating.

  • Some hard parts of organism are preserved in form of molds in soft sediments.
  • The outline and important details of the hard part is preserved when the mold dissolves away.
  • Fossil molds are representative on the internal outline of the hard parts of organisms.
  • They are usually recognized as a part of body fossil in a section.

learn more:

Fossils brainly.com/question/7382392

#learnwithBrainly

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Mechanics: design a decision tree to determine if an object is experiencing an unbalanced force, and using newton's laws of moti
masya89 [10]

Answer:

The decision designer is a step-wise process

Explanation:

A typical decision tree will be like this:

Are there any forces?

YES - then calculate the resultant forces              NO - Then no calculations are needed

IF YES - Are the forces balanced?                         NO - Then no calculations

IF YES - Then calculations can be done.

Resolve the forces to find the resultant of the forces in the question.

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what happens to the water after it rains? a. precipitation b. runoff c. condensation user: what do organisms from the ocean use
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The rain gets evaporated in to water vapor and is returned to the clouds where they go through condensation and then they poud down as rain or A.K.A,  Precipitation.
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A 1750kg bumpercar moving at 1.50m/s to the right collides elastically with a 1450kg car going to the left at 1.10m/s. The 1750k
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A boat is travelling due west at a speed of 47 miles per hour. If the boat started off 170 miles directly north of the city of S
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A thin, metallic spherical shell of radius 0.347 m0.347 m has a total charge of 7.53×10−6 C7.53×10−6 C placed on it. A point cha
USPshnik [31]

Answer:

E = 12640.78 N/C

Explanation:

In order to calculate the electric field you can use the Gaussian theorem.

Thus, you have:

\Phi_E=\frac{Q}{\epsilon_o}

ФE: electric flux trough the Gaussian surface

Q: net charge inside the Gaussian surface

εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2

If you take the Gaussian surface as a spherical surface, with radius r, the electric field is parallel to the surface anywhere. Then, you have:

\Phi_E=EA=E(4\pi r^2)=\frac{Q}{\epsilon_o}\\\\E=\frac{Q}{4\pi \epsilon_o r^2}

r can be taken as the distance in which you want to calculate the electric field, that is, 0.795m

Next, you replace the values of the parameters in the last expression, by taking into account that the net charge inside the Gaussian surface is:

Q=7.53*10^{-6}C+3.65*10^{-6}C=1.115*10^{-5}C

Finally, you obtain for E:

E=\frac{1.118*10^{-5}C}{4\pi (8.85*10^{-12C^2/Nm^2})(0.795m)^2}=12640.78\frac{N}{C}

hence, the electric field at 0.795m from the center of the spherical shell is 12640.78 N/C

3 0
2 years ago
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