<u>Answer:</u> The amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of hex-3-ene = 5.84 g
Molar mass of hex-3-ene = 82.14 g/mol
Putting values in equation 1, we get:
The chemical equation for the conversion of hex-3-ene to 3-hexanol follows:
![\text{hex-3-ene}+H_2O\xrightarrow []{10\% H_2SO_4} \text{3-hexanol}](https://tex.z-dn.net/?f=%5Ctext%7Bhex-3-ene%7D%2BH_2O%5Cxrightarrow%20%5B%5D%7B10%5C%25%20H_2SO_4%7D%20%5Ctext%7B3-hexanol%7D)
By Stoichiometry of the reaction:
1 mole of hex-3-ene produces 1 mole of 3-hexanol
So, 0.0711 moles of hex-3-ene will produce = 
of 3-hexanol
Now, calculating the mass of 3-hexanol from equation 1, we get:
Molar mass of 3-hexanol = 102.2 g/mol
Moles of 3-hexanol = 0.0711 moles
Putting values in equation 1, we get:
To calculate the percentage yield of 3-hexanol, we use the equation:
Experimental yield of 3-hexanol = 4.33 g
Theoretical yield of 3-hexanol = 7.27 g
Putting values in above equation, we get:
Hence, the amount of hex-3-ene used is 0.0711 moles and the percent yield of 3-hexanol is 59.56 %
