Question

The equation for photon energy, E, is E=hcλ where h = 6.626×10−34 J⋅s (Planck's constant) and c = 2.99×108 m/s (the speed of light). What is the wavelength, λ, of a photon that has an energy of E = 4.61×10−19 J ?

Answer 1

Answer:

9.133×10^-6 m

Explanation:

A photon is the smallest discrete amount or quantum of electromagnetic radiation. It is the basic unit of all light. Photons are always in motion and, in a vacuum, travel at a constant speed to all observers of 3 x 10^8 m/s.

From the question, the following details were supplied;

Energy of the photon (E) = 4.61×10^−19 J

Speed of light (c) = 2.99×10^8 m/s

Plank's constant (h) = 6.626×10^−34 J⋅s

Wavelength of the photon (λ)= ??? The unknown

From

E=hc/λ

λ= hc/E

Substituting values

λ= 6.626×10^−34 × 2.99×10^8/ 4.61×10^−19

λ= 91.33×10^-7 m

λ= 9.133×10^-6 m