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madam [21]
3 years ago
13

the following data were collected. time, s [A], M 0 1.00 1 0.430 2 0.270 3 0.200 4 0.160 What is the order of the reaction and t

he rate constant
Chemistry
1 answer:
Tems11 [23]3 years ago
7 0

Answer:

I'll give you the graphs that you need to look at:1st order: the graph you need to make is ln[A] vs t. If you get a straight line, the reaction is 1st order and the slope will equal to the rate constant K.2nd order: the graph you need to make is 1/ln[A] vs t. If this graph shows a straight line, the reaction is 2nd order and the slope will equal the rate constant K.

Explanation:

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Which statement best describes the collisions of gas particles according to the kinetic-molecular theory?
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7 0
4 years ago
Read 2 more answers
What is the volume of 1.56 kg of a compound whose molar mass is 81.86 g/mole and whose density is 41.2 g/ml?
hjlf

Answer:

v = 37.9 ml

Explanation:

Given data:

Mass of compound = 1.56 kg

Density = 41.2 g/ml

Volume of compound = ?

Solution:

First of all we will convert the mass into g.

1.56 ×1000 = 1560 g

Formula:

D=m/v

D= density

m=mass

V=volume

v = m/d

v =  1560 g / 41.2 g/ml

v = 37.9 ml

7 0
3 years ago
!!!HELP ASAP!!! Which of the following is an example of a chemical change?
VikaD [51]
C. A solid dissolving
4 0
3 years ago
The vapor pressure of benzene is 73.03 mm Hg at 25°C. How many grams of estrogen (estradiol), C18H24O2, a nonvolatile, nonelectr
alexira [117]

Answer:

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

Explanation:

The relative lowering of vapor pressure of solution containing non volatile solute is equal to mole fraction of solute.

\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}

Where:

p_o = Vapor pressure of pure solvent

p_s = Vapor pressure of the solution

n_1 = Number of moles of solvent

n_2 = Number of moles of solute

p_o = 73.03 mmHg

p_s= 71.61 mmHg

n_1=\frac{216.7 g}{78.12 g/mol}=2.7739 mol

\frac{73.03 mmHg-71.61 mmHg}{73.03 mmHg}=\frac{n_2}{2.7739 mol+n_2}

n_2=0.05499 mol

Mass of 0.05499 moles of estrogen :

= 0.05499 mol × 272.4 g/mol = 14.9802 g

14.9802 grams of estrogen must be added to 216.7 grams of benzene.

6 0
3 years ago
Please help/show work!
Keith_Richards [23]

Answer:

7.00335g

Explanation:

n=\frac{V}{V_m} \\n = \frac{11.2}{22.4} \\n= 0.5 mol

n=\frac{m}{M} \\m=nM\\m=(0.5)(14.0067)\\m=7.00335g

3 0
2 years ago
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