It means that 22.5×10^5 J of heat is required to change 1 kg of water into steam.
Latent heat of vaporization is amount of energy required to change 1 gram (in this example 1 kilogram) of material from the liquid to the gaseous state at its boiling point.
Boiling point of the water is 100°C.
Joule (J) is the standard unit for energy (in this example heat).
Evaporization is phase change process in which the water changes from a liquid to a gas (water vapor). Fore example, solar radiation can be the source of energy for evaporation.
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Answer:
(−ΔH°1)+12(−ΔH°2)+(ΔH°3)+(ΔH°4)
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Answer:
Final temperature of the gas = -146.63 °C
Explanation:
At constant pressure, volume and temperature of the gases are related as:

Where,
V1 = Initial volume = 1.00 L
V2 = Final volume = 2.40 L
T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K
Now, substitute the values in the above equation,



T2 = 126.52 K
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
T( °C) = T(K) - 273.15
= 126.52 - 273.15 = -146.63 °C
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Explanation: REEEEEEEEE
Answer:
2.0 grams, hope it helps!