Answer:
2-ethoxy-2-methylpropan-1-ol
Explanation:
On this reaction, we have an "<u>epoxide"</u> (2-methyl-1,2-epoxypropane). Additionally, we have <u>acid medium</u> (due to the sulfuric acid
). The acid medium will produce the <u>hydronium ion</u> (
). This ion would be attacked by the oxygen of the epoxide. Then a <u>carbocation</u> would be produced, in this case, the most stable carbocation is the <u>tertiary one</u>. Then an <u>ethanol</u> molecule acts as a nucleophile and will attack the carbocation. Finally, a <u>deprotonation </u>step takes place to produce <u>2-ethoxy-2-methylpropan-1-ol</u>.
See figure 1
I hope it helps!
Answer:
See explanation
Explanation:
Air contains a mixture of several molecules and compounds such as oxygen and carbon dioxide.
Answer:
?? no entiendo la pregunta?...pero gracias por los puntos free UvU
Explanation:
All the answers are on the actual periodic table. You should never be told to remember it so I think this is a recourse you are allowed to look at whilst doing your homework lol :) all the answers are written on it hope it helps
<span>1.Remove the ending of the second element, and add "ide" just like in ionic compounds
2.When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound
3.If there is only one of the first element, you can drop the prefix
<span>4.If there are two vowels in a row that sound the same once the prefix is added (they "conflict"), the extra vowel on the end of the prefix is removed</span></span>