Answer : The electron domain and molecular geometry of
are, tetrahedral and bent or angular respectively.
Explanation :
Formula used:
![\text{Number of electrons}=\frac{1}{2}[V+N-C+A]](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electrons%7D%3D%5Cfrac%7B1%7D%7B2%7D%5BV%2BN-C%2BA%5D)
where,
V = number of valence electrons present in central atom
N = number of monovalent atoms bonded to central atom
C = charge of cation
A = charge of anion
First we have to determine the hybridization of the
molecules.
![\text{Number of electrons}=\frac{1}{2}\times [7+1]=4](https://tex.z-dn.net/?f=%5Ctext%7BNumber%20of%20electrons%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20%5B7%2B1%5D%3D4)
The number of electrons are 4 that means the hybridization will be
and the electronic geometry of the molecule will be tetrahedral.
But as there are two atoms around the central bromine, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent or angular.
Hence, the electron domain and molecular geometry of
are, tetrahedral and bent or angular respectively.