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just olya [345]
3 years ago
14

The electron domain and molecular geometry of bro2- is __________.

Chemistry
2 answers:
-Dominant- [34]3 years ago
6 0

Answer : The electron domain and molecular geometry of BrO_2^- are, tetrahedral and bent or angular respectively.

Explanation :

Formula used:

\text{Number of electrons}=\frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

First we have to determine the hybridization of the BrO_2^-  molecules.

\text{Number of electrons}=\frac{1}{2}\times [7+1]=4

The number of electrons are 4 that means the hybridization will be sp^3 and the electronic geometry of the molecule will be tetrahedral.

But as there are two atoms around the central bromine, the third and fourth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent or angular.

Hence, the electron domain and molecular geometry of BrO_2^- are, tetrahedral and bent or angular respectively.

Rus_ich [418]3 years ago
3 0
The answer is Tetrahedral,bent
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Which process releases energy that eventually produces lightning in the thunderstorm?
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4 0
3 years ago
1. Compare masses: a) 0,4mol CO₂ and 0,6mol H₂O ; b) 0,135mol H₂SO₄ and 0,5mol HCI.
bixtya [17]

Answer:

you can now deduct which one is greater or smaller and by how much.

Explanation:

no of moles= mass/molar mass

1ai) 0.4 = m/ ( 12 + (16*2)

m= 0.4* 44

m= 17.6g

ii) 0.6= m/( 2*1 + 16)

m= 0.6 *18

m= 10.8g

b) 0.135 = m/ ( 2*1 +32 + (16*4)

m= 0.135* 98

m= 13.23g

ii) 0.5= m/ (1+35.5)

m= 0.5*36.5

m= 18.25g

2. Avogadro's Number = 6.02×10²³

1 mol of any element= 6.02×10²³ particles

a) 0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules

ii) 0.3 mol of CO2= (6.02×10²³) * 0.3

= 1.806 × 10²³ molecules

Ans: 0.3 mol of CO2

bi) 0.25 mol of HCl= (6.02×10²³) * 0.25

= 1.505 × 10²³ molecules

bii) - find the no of moles first:

no of moles= mass/molar mass

n= 3.4g/ 34g →mr of H2S in g=2+32= 34g

n= 0.l mol

- use the Avogadro Number.

0.1 mol of H20= (6.02×10²³) * 0.1

= 6.02×10²² molecules.

biii) here you're given the density, use it to find the mass of acetic acid.

ρ = 1049 g/ml

ρ = m/v, where v=5 ml

1049 = m/ 5

m= ρ*v

m= 1049*5

m= 5245 g

• convert this into moles.

mr of CH3COOH= 12 + 3+ 12+ 16+ 16+ 1

= 60

mr in g = 60g

n= m/mr

n= 5245/ 60

n= 87. 41666...

n= 87.4 moles

•using Avogadro's Number:

87.4 moles of acetic acid=(6.02×10²³)*87.4

= 2.25148* 10²⁵

= 2.25 * 10²⁵ molecules

thus, the ans for this is 5 ml of acetic acid.

7 0
2 years ago
Help <br> whoever answers all gets marked brainliest
Lelechka [254]

#1

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#2

Yes here we can see the dots and crosses clearly.

  • Dot and crosses digram

#3

It's Methane or CH_4

  • 4 single bonds

#4

There is no double bond

6 0
2 years ago
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