Explanation:
Let us assume that the concentration of [
and 
is equal to x. Then expression for 
for the given reaction is as follows.
![K_{w} = [OH^{-}][H^{+}]](https://tex.z-dn.net/?f=K_%7Bw%7D%20%3D%20%5BOH%5E%7B-%7D%5D%5BH%5E%7B%2B%7D%5D)
Now, we will take square root on both the sides as follows.
![[H^{+}] = 8.2 \times 10^{-8}](https://tex.z-dn.net/?f=%5BH%5E%7B%2B%7D%5D%20%3D%208.2%20%5Ctimes%2010%5E%7B-8%7D)
M
Thus, we can conclude that the 
concentration in neutral water at this temperature is 
M.
Rust is an iron oxide and formed by the reaction of iron and oxygen in the presence of moisture. So the answer would be C
1.25 g x 22.4 l / 1 mol = 28 g/mol
Density = mass / volume
Density = 7.5 g / 5.0 cm3
Density = 1.5 g/cm3
Answer:
Oxygen Gas
Explanation:
The balanced equation shows us the reactant ratio of the reaction.
This means that for every one mole of CH3CH2OH, we need 3 moles of O2 to react with it. Because we need more O2, (3x as much) than ethanol and we have the same given amount (1 mole of each), the oxygen will be the limiting reagent. (1 mole of oxygen would only require 1/3 moles of ethanol to react).
Hope this helped!
