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grigory [225]
3 years ago
13

The atomic number is very important, as it indicates

Chemistry
1 answer:
ankoles [38]3 years ago
5 0

Answer:

B.) the number of protons and also the number of electrons in an element

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The active ingredient in some oral anesthetics used in sore throat sprays. what is the molar mass of phenol?
raketka [301]

Answer: Molecular mass of the phenol is 94g/mol.

Explanation:

Phenol is an active ingredient in some oral anesthetics used in sore throat sprays.It is used as anesthetics to cure minor sour throat pain , minor mouth irritations etc.

For Example : Cramex , Chloraseptic sprays contains phenol as an active ingredient.

Phenol has a molecular formula of C_6H_5OH

Molecular mass of the phenol = 6(mass of carbon)+5(mass of hydrogen)+1(mass of oxygen)+1(mass of hydrogen) = 6(12)+5(1)+1(16)+(1) = 94 g/mol

6 0
3 years ago
Read 2 more answers
In an electrically heated boiler, water is boiled at 140°C by a 90 cm long, 8 mm diameter horizontal heating element immersed in
RideAnS [48]

Explanation:

The given data is as follows.

Volume of water = 0.25 m^{3}

Density of water = 1000 kg/m^{3}

Therefore,  mass of water = Density × Volume

                       = 1000 kg/m^{3} \times 0.25 m^{3}

                       = 250 kg  

Initial Temperature of water (T_{1}) = 20^{o}C

Final temperature of water = 140^{o}C

Heat of vaporization of water (dH_{v}) at 140^{o}C  is 2133 kJ/kg

Specific heat capacity of water = 4.184 kJ/kg/K

As 25% of water got evaporated at its boiling point (140^{o}C) in 60 min.

Therefore, amount of water evaporated = 0.25 × 250 (kg) = 62.5 kg

Heat required to evaporate = Amount of water evapotaed × Heat of vaporization

                           = 62.5 (kg) × 2133 (kJ/kg)

                           = 133.3 \times 10^{3} kJ

All this heat was supplied in 60 min = 60(min)  × 60(sec/min) = 3600 sec

Therefore, heat supplied per unit time = Heat required/time = \frac{133.3 \times 10^{3}kJ}{3600 s} = 37 kJ/s or kW

The power rating of electric heating element is 37 kW.

Hence, heat required to raise the temperature from 20^{o}C to 140^{o}C of 250 kg of water = Mass of water × specific heat capacity × (140 - 20)

                      = 250 (kg) × 40184 (kJ/kg/K) × (140 - 20) (K)

                     = 125520 kJ  

Time required = Heat required / Power rating

                       = \frac{125520}{37}

                       = 3392 sec

Time required to raise the temperature from 20^{o}C to 140^{o}C of 0.25 m^{3} water is calculated as follows.

                    \frac{3392 sec}{60 sec/min}

                     = 56 min

Thus, we can conclude that the time required to raise the temperature is 56 min.

4 0
3 years ago
PLEASE FILL IN THE BLANKS IM DYING OMGGGGG
Sidana [21]
Neutrons: +1
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5 0
3 years ago
What is the most likely reason that mendeleev placed tellurium before iodine? mendeleev observed that tellurium has chemical pro
Len [333]
<span>it is A. Mendeleev observed that tellurium has chemical....</span>
5 0
3 years ago
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If it takes 2000 years to weather 1 cm of limestone, how long will it take to weather 5 cm of limestone?
Anna71 [15]

Answer:10,0000 years

Explanation:

If it takes 2000 years to weather 1cm of limestone

It will take 5*2000 years to weather 5cm of limestone. This gives us 10000 years.

3 0
3 years ago
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