Answer:
Height = 1.9493 cm
Width = 1.9493 cm
Depth = 1.9493 cm
Solution:
Data Given:
Mass = 20 g
Density = 2.7 g/mL
Step 1: Calculate the Volume,
As,
Density = Mass ÷ Volume
Or,
Volume = Mass ÷ Density
Putting values,
Volume = 20 g ÷ 2.7 g/mL
Volume = 7.407 mL or 7.407 cm³
Step 2: Calculate Dimensions of the Cube:
As we know,
Volume = length × width × depth
So, we will take the cube root of 7.407 cm³ which is 1.9493 cm.
Hence,
Volume = 1.9493 cm × 1.9493 cm × 1.9493 cm
Volume = 7.407 cm³
Answer:
![T_2= 31.9\°C](https://tex.z-dn.net/?f=T_2%3D%2031.9%5C%C2%B0C)
Explanation:
Hello there!
In this case, it is possible to propose an energy balance in order to illustrate how the heat released by the reaction is absorbed by the water:
![-Q_{rxn}=Q_{water}](https://tex.z-dn.net/?f=-Q_%7Brxn%7D%3DQ_%7Bwater%7D)
Thus, since the heat released by the reaction is -112 kJ (-112000 J), it is possible to define the hear absorbed by the water in terms of mass, specific heat and temperature change:
![-(-112000J)=m_{water}C_{water}(T_2-T_1)](https://tex.z-dn.net/?f=-%28-112000J%29%3Dm_%7Bwater%7DC_%7Bwater%7D%28T_2-T_1%29)
In such a way, it is possible to define the final temperature as shown below:
![T_2=23.8\°C+\frac{112000J}{3300g*4.18\frac{J}{g\°C} }\\\\T_2= 31.9\°C](https://tex.z-dn.net/?f=T_2%3D23.8%5C%C2%B0C%2B%5Cfrac%7B112000J%7D%7B3300g%2A4.18%5Cfrac%7BJ%7D%7Bg%5C%C2%B0C%7D%20%7D%5C%5C%5C%5CT_2%3D%2031.9%5C%C2%B0C)
Best regards!
Answer:
2.1 x 10^24 Cr ions
Explanation:
You need to multiply the 3.5 mol by the Avogrado's number (6.022 x 10^23) to get your answer.
As the atomic radius decreases, it becomes harder to remove an electron that is closer to a more positively charged nucleus. ... They experience a weaker attraction to the positive charge of the nucleus. Ionization energy increases from left to right in a period and decreases from top to bottom in a group.