Answer:
To the nearest hundred dollars, the car will be worth $17,900 by 2005
Step-by-step explanation:
Firstly, we need to write the depreciation equation
We have this as:
V = I(1 - r)^t
V is the present value which is what we want to calculate
I is the initial value, the amount the cad was bought which is $22,000
r is the rate of change which is 5% = 5/100 = 0.05
t is the time difference which is 2005-2001 = 4
Substituting all these into the depreciation equation, we have it that
V = 22,000(1 -0.05)^4
V = $17,919.1375
To the nearest hundred dollars, that would be;
$17,900
Answer:
Option C i.e. 2 and 9, constants have a fixed value is a correct option.
Step-by-step explanation:
In algebra, a constant is basically a fixed value.
Sometimes, a constant is a number for a letter such as a, b, or c for a fixed number.
For example: in ''2x+7=3'', 7 and 3 are constants.
- <em>Please note that the number with variable x in the term is a coefficient.</em>
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In our case:
Given the equation
Therefore, 2 and 9 are constants, having a fixed value.
Thus, option C i.e. 2 and 9, constants have a fixed value is a correct option.
Answer:
When it comes to investing, compound interest is better since it allows funds to grow at a faster rate than they would in an account with a simple interest rate.
Answer:
c
Step-by-step explanation:
c
Answer:
Es 60
Step-by-step explanation:
