Answer:
The bumper will be able to move by 0.01155m.
Explanation:
The magnitude of deceleration of the car in the front end collision.
This is the deceleration of the car that is generated to stop due to a front end collision.
4 km/h = 1.11 m/s
Now, the initial speed of the bumper in the relation of car, Vi = 0
Now, the initial speed of the bumper in the relation of car, Vf = 1.11 m/s
Use the below equation:
Thus, the bumper can move relative to the car is 0.01155 m .
Hope the picture helps I was a bit confused tho sorry for the mistakes too. Sorry next time please explain the question more.
Answer:
Fx = -7042.86N (Taking the right as positive sense of motion)
Fy = 2154.29N.
Explanation:
The full solution can be found in the attachment below. The approach to the solution involves the summation of the respective components of the momentum along the horizontal and vertical axis.
To the right is taken as positive sense of motion and the left as negative sense of motion.
The basic statement of Newtown's second law have been used which is
M(v2 – v1) = Ft
See the attachment below for the complete calculation procedure.
Answer:
A = [m/s]
B = [m/s²]
Explanation:
Assuming that V has SI units of m/s, then A and BT must also have units of m/s.
A = [m/s]
BT = [m/s]
Since T has SI units of s:
B [s] = [m/s]
B = [m/s²]
Answer:
10.6 s
Explanation:
First of all, let's convert both speeds into m/s:
- Cheetah:
- Gazelle:
Taking as reference the position x = 0, the position of the cheetah at time t is
while the position of the gazelle, which starts 68.8 m ahead, is
The cheetah catches the gazelle when the two positions are equal:
and substituting the speeds and solving for t, we find the time at which the cheetah reaches the gazelle: