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fenix001 [56]
3 years ago
8

What is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up

Physics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

i think it's 1400

Explanation:

w = Force x displacement

w = 400 x 3.5

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<h2>Answer:</h2>

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<h2>Explanation:</h2>

In the question,

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So,

From the <u>equations of the motion</u>,

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Also,

Finally, the angle made is 2 degrees with the horizontal.

So,

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Now,

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v=u+at\\vsin20=0+9.8(t)\\t=\frac{v.sin20}{9.8}

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\frac{v.sin20}{9.8}=\frac{61}{v.cos20}\\v^{2}.sin20.cos20=597.8\\v^{2}=1860.56\\v=43.13\,m/s

<em><u>Therefore, the velocity with which the arrow was shot by the archer is 43.13 m/s.</u></em>

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marusya05 [52]

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