Recall the definition of the cross product with respect to the unit vectors:
i × i = j × j = k × k = 0
i × j = k
j × k = i
k × i = j
and that the product is anticommutative, so that for any two vectors u and v, we have u × v = - (v × u). (This essentially takes care of part (b).)
Now, given a = 8i + j - 2k and b = 5i - 3j + k, we have
a × b = (8i + j - 2k) × (5i - 3j + k)
a × b = 40 (i × i) + 5 (j × i) - 10 (k × i)
… … … … - 24 (i × j) - 3 (j × j) + 6 (k × j)
… … … … + 8 (i × k) + (j × k) - 2 (k × k)
a × b = - 5 (i × j) - 10 (k × i) - 24 (i × j) - 6 (j × k) - 8 (k × i) + (j × k)
a × b = - 5k - 10j - 24k - 6i - 8j + i
a × b = -5i - 18j - 29k
D) A gallon of gasoline definitely. Gas is like, if not a chemical. It will have the most.
~Silver
Answer:
2.25 Ω
Explanation:
Standard equation
V = IR re-arrange to
V /I = R then sub in the values given
9 / 4 = 2.25 Ω
Answer:
Is considered as not as dangerous as AC
Answer:
5.5Ω
Explanation:
The circuit diagram shown is a parallel arrangement. To solve this problem for the equivalent resistance,
R1 = 10Ω
R2 = 20Ω
R3 = 30Ω
For circuits in parallel, equivalent resistance is ;
= 
Now insert the parameters and solve;
= 
= 
= 
Rt = 5.5Ω
