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3 years ago

Question 1 2 pts Explain what causes a solution to be a strong acid.

Physics

1 answer:

lubasha [3.4K]3 years ago

5 0

Answer:

Cuanto más fuerte es el ácido, más rápido se disocia para generar H +start superscript, plus, end superscript. Por ejemplo, el ácido clorhídrico (HCl) se disocia completamente en iones hidrógeno y cloruro cuando se mezcla con agua, por lo que se considera un ácido fuerte.

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Water is boiled at 300 kPa pressure in a pressure cooker. The cooker initially contains 3 kg of water. Once boiling started, it

Inessa [10]

Answer:

The average rate of energy transfer to the cooker is 1.80 kW.

Explanation:

Given that,

Pressure of boiled water = 300 kPa

Mass of water = 3 kg

Time = 30 min

Dryness friction of water = 0.5

Suppose, what is the average rate of energy transfer to the cooker?

We know that,

The specific enthalpy of evaporate at 300 kPa pressure

$h_{f}=561.47\ kJ/kg$

$h_{fg}=2163.8\ kJ/kg$

We need to calculate the enthalpy of water at initial state

$h_{1}=h_{f}$

$h_{1}=561.47\ kJ/kg$

We need to calculate the enthalpy of water at final state

Using formula of enthalpy

$h_{2}=h_{f}+xh_{fg}$

Put the value into the formula

$h_{2}=561.47+0.5\times2163.8$

$h_{2}=1643.37\ kJ/kg$

We need to calculate the rate of energy transfer to the cooker

Using formula of rate of energy

$Q=\dfrac{m(h_{2}-h_{1})}{t}$

Put the value into the formula

$Q=\dfrac{3\times(1643.37-561.47)}{30\times60}$

$Q=1.80\ kW$

Hence, The average rate of energy transfer to the cooker is 1.80 kW.

3 0

3 years ago

Estimate the acceleration you subject yourself to if you walk into a brick wall at normal walking speed. (Make a reasonable esti

xenn [34]

Answer:

From certain assumptions that the walking speed is 2 m/s, and the stop time is 0.1 s the acceleration would be -20 m/s

Explanation:

Using the average acceleration formula:

$a=\frac{\Delta v}{\Delta t}$ where $\Delta v$ and $\Delta t$ are the changes in the speed and time respectively.

We have by assuming that the walking speed is 2 m/s and the stop time is 0.1s which is equal to the change in time during the stopping.

$\Delta v=v_f-v_i=0-2 m/s=-2 m/s$ , where $v_i,v_f$ are the initial speed and final speed respectively, and $\Delta t=0.1 s$

Plugging the previous in the average acceleration formula we get

$a=\frac{-2}{0.1}=-20\, m/s$ where the minus sign indicates an acceleration in the opposite direction of the motion (or in other word opposite to the speed's direction).