Answer:
positive plate
E = 5.764 KV / m
W = 490eV or 7.85 * 10^-17 J
E_p = 4.74 *10^(-12) eV
E_k = 490 eV
Explanation:
part a
The potential difference between two plates = 490 V
Distance between two plates = 8.5 cm
Answer: The positive plate is at higher potential because of convention.
part b
Electric Field between the plates
E = V / d
E = 490 / 0.085 = 5.764 KV / m
Answer: Electric Field between the plates E = 5.764 KV / m
part c
Work done by electric field
W = V*q
W = 490 * 1.602*10^-19
W = 7.85 * 10^-17 J
or W = 490 eV
Answer: Work done by electric field W = 490eV or 7.85 * 10^-17 J
part d
Potential Energy of an electron gained:
E_p = m_e * g * d / (1.602*10^-19)
E_p = 9.109*10^-31* 9.81 * 0.085 / (1.602*10^-19)
E_p = 4.74 *10^(-12) eV
Very very small E_p approximately 0
Answer: Potential Energy of an electron gained E_p = 4.74 *10^(-12) eV or 0.
part e
Kinetic Energy of an electron gained:
W - E_p = E_k
E_k = 490eV - 4.74*10^(-12)eV
E_k = 490 eV
Answer: Kinetic Energy of an electron gained E_k = 490 eV
Answer:
The planet´s orbital period will be one-half Earth´s orbital period.
Explanation:
The planet in orbit, is subject to the attractive force from the sun, which is given by the Newton´s Universal Law of Gravitation.
At the same time, this force, is the same centripetal force, that keeps the planet in orbit (assuming to be circular), so we can put the following equation:
Fg = Fc ⇒ G*mp*ms / r² = mp*ω²*r
As we know to find out the orbital period, as it is the time needed to give a complete revolution around the sun, we can say this:
ω = 2*π / T (rad/sec), so replacing this in the expression above, we get:
Fg = Fc ⇒ G*mp*ms / r² = mp*(2*π/T)²*r
Solving for T²:
T² = (2*π)²*r³ / G*ms (1)
For the planet orbiting the sun in Andromeda, we have:
Ta² = (2*π)*r³ / G*4*ms (2)
As the radius of the orbit (distance to the sun) is the same for both planets, we can simplify it in the expression, so, if we divide both sides in (1) and (2), simplifying common terms, we finally get:
(Te / Ta)² = 4 ⇒ Te / Ta = 2 ⇒ Ta = Te/2
So, The planet's orbital period will be one-half Earth's orbital period.
Answer:
m(P4) = 46.175 (grams)
m (KClO3) = 149 (grams)
Explanation:
1) n(P4) = n(P4O10);
m(P4)/M(P4) = m(P4O10)/M(P4O10);
m(P4) = M(P4)*m(P4O10)/M(P4O10)
= 123.90*105.8/283.89
= 46.175 (grams)
2) Analogously, 10n(P4O10) = 3n(KClO3)
m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
= 10*122.55*105.8/283.89/3
= 149 (grams).
Answer:
y = 1.19 m and λ = 8.6036 10⁻⁷ m
Explanation:
This is a slit interference problem, the expression for destructive interference is
d sin θ = m λ
indicate that for the angle of θ = 35º it is in the third order m = 3 and the separation of the slits is d = 4.50 10⁻⁶ m
λ = d sin θ / m
let's calculate
λ = 4.50 10⁻⁶ sin 35 /3
λ = 8.6036 10⁻⁷ m
for the separation distance from the central stripe, we use trigonometry
tan θ= y / L
y = L tan θ
the distance L is measured from the slits, it indicates that the light source is at x = 0.30 m from the slits
L = 2 -0.30
L = 1.70 m
let's calculate
y = 1.70 tan 35
y = 1.19 m
A thermostat is a switch that operates itself when the temperature
goes above or below a temperature that the user can set.
-- Before you go to bed, you set the thermostat for 65° .
If the temperature in the house goes below 65° during the night,
the thermostat turns on the furnace, and keeps it running until
the house warms up to 65°. Then it shuts the furnace off.
-- After breakfast, you set the thermostat for 75°.
If the temperature in the house goes above 75°, during the day,
the thermostat turns on the air conditioner, and keeps it running until
the house cools down to 75°. Then it shuts the air conditioner off.
-- On Sunday morning, you put the slow cooker on the kitchen counter,
and you throw in a big roast, a sliced onion, some baby carrots, some
sliced potatoes, some vegetable stock, salt, pepper, garlic, chili powder,
and tomato paste. Then you put the cover on, turn the power on, and
set the slow cooker to "LOW". The heater in the slow cooker turns on.
Whenever the temperature in the crock gets higher than 160°, the
thermostat in the slow cooker turns off the heater, and keeps it off
until the crock cools down to 160°. Then the thermostat turns the
heater on again.
By dinner time, you have a hot, juicy, scrumptious pot roast, ready
to eat. It's not too hot, not too cold, not too tough, not dried out, and
it melts in your mouth.
You're still thinking about it when you go to bed, and your mom gives you
a slice to take to school for your lunch on Monday.
