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Degger [83]
3 years ago
6

In a position vs time graph if the line is curved then the motion of the object may be

Physics
1 answer:
Elza [17]3 years ago
5 0

Answer:

tge motion of the object is not constant or uniform

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Suppose you have two small pith balls that are 5.5 cm apart and have equal charges of -29 nc?
zysi [14]
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.

The Coulomb force between the two balls is:
F= k_e \frac{ q_1 q_2}{r^2}
where k_e=8.99\cdot10^9~N m^2 C^{-2} is the Coulomb's constant, q_1=q_2=29~nC=29\cdot 10^{-9}~C is the intensity of the two charges, and r=5.5~cm=0.055~m is the distance between them.

Substituting these numbers into the equation, we get
F=2.5~10^{-3}~N

The force is repulsive, because the charges have same sign and so they repel each other.
6 0
3 years ago
Looking at the velocity vs time graph, between points b and c on the graph, the object was
mihalych1998 [28]
Between B and C, the object was going at a constant velocity; it is going 60 m/min consistently for that time frame.
8 0
3 years ago
A 45 kg object has a momentum of 225 kg-m/s northward. What is the object's velocity?
melomori [17]

Answer: 5 m/s North

Explanation:

Velocity = Momentum/Mass

Velocity = 225 kg*m/s/45kg

Velocity = 5 m/s North

3 0
2 years ago
How much would a 70 kg student weigh on Pluto? (massPluto = 1.25 x 1022 kg, radiusPluto = 1.20 x 106 m)
mote1985 [20]

Answer: the weight would be 4.6 (I think i don’t know))

Explanation:

6 0
3 years ago
A(n) 71.1 kg astronaut becomes separated from the shuttle, while on a space walk. She finds herself 70.2 m away from the shuttle
denpristay [2]

Answer:

10.347 minutes.

Explanation:

According to F = ma, she exerts force on camera of the magnitude

F = 0.67Kg*12m/s^{2} = 8.04N, assuming it took her one second to accelerate camera to 12m/s, then by newtons third law, which says every action has equal and opposite reaction , the camera exerts the same amount of force on the astronaut which gives her acceleration of a = \frac{8.04N}{70.2Kg} = 0.1130801680m/s^2.

and velocity of V = 0.1130801680m/s.

at this velocity , the astronaut has to cover the distance of 70.2 meters, it will take her 620.7985075s = 10.347 min to get to the shuttle (using S = vt).

4 0
3 years ago
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