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3 years ago

If the price of each shirt sold by Target is 150% of the wholesale price, what is the wholesale price of a $15.99 shirt?

Mathematics

2 answers:

cupoosta [38]3 years ago

8 0

$\frac{15.99}{150*100}=10.66$

The wholesale price of a shirt worth $15.99 is $10.66.

Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

- Cutiepatutie ☺❀❤

patriot [66]3 years ago

4 0

Answer:

10.66

Step-by-step explanation:

15.99÷150×100=10.66

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Cassie has 1/2 pound of sugar in her cabinet.Her cake recipe calls

BigorU [14]

Answer:

2 cakes with the sugar she has and there will still be some sugar left.

Step-by-step explanation:

Amount of sugar in the cabinet of Cassie = 1/2 pound

Amount of sugar required by Cassie to make her cake recipe = 2/10 pound

= 1/5 pounds

Then

The number of cakes that Cassie can make = (1/2)/(1/5)

= 5/2

= 2 1/2

6 0

3 years ago

For the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled b

dmitriy555 [2]

Answer:

2019.

Step-by-step explanation:

We have been given that for the years from 2002 and projected to 2024, the national health care expenditures H, in billions of dollars, can be modeled by $H = 1,500e^{0.053t}$ where t is the number of years past 2000.

To find the year in which national health care expenditures expected to reach $4.0 trillion (that is, $4,000 billion), we will substitute $H=4,000$ in our given formula and solve for t as:

$4,000= 1,500e^{0.053t}$

$\frac{4,000}{1,500}=\frac{ 1,500e^{0.053t}}{1,500}$

$\frac{8}{3}=e^{0.053t}$

$e^{0.053t}=\frac{8}{3}$

Take natural log of both sides:

$\text{ln}(e^{0.053t})=\text{ln}(\frac{8}{3})$

$0.053t\cdot \text{ln}(e)=\text{ln}(\frac{8}{3})$

$0.053t\cdot (1)=0.9808292530117262$

$\frac{0.053t}{0.053}=\frac{0.9808292530117262}{0.053}$

$t=18.506212320$

So in the 18.5 years after 2000 the expenditure will reach 4 trillion.

$2000+18.5=2018.5$

Therefore, in year 2019 national health care expenditures are expected to reach $4.0 trillion.

7 0

4 years ago

Help me<br> Line ℓ is perpendicular to line m. Find the value of x and w.

wel

138° + w° = 180° (sum of angle on a straight line)
w° = 180° - 138°
w = 42

19° + x° + w° = 90°
sub. in w=42,
19° + x° + 42° = 90°
x° = 90° - 19° - 42°
x° = 29°
x = 29

6 0

3 years ago

Read 2 more answers

A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean

elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}$ ). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

3 0

3 years ago

Identify the volume of a cone with base area 64π m2 and a height 4 m less than 3 times the radius, rounded to the nearest tenth.

melomori [17]

V=basearea times 1/3 times height
basearea=6<span>4π m2
hmm, they try to make it difficult

basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9

h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20

v=1/3*64pi*20=1280pi/3 m^3=1350.4

C
</span>

4 0

3 years ago