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Alisiya [41]
3 years ago
15

Does anyone here live in South Carolina and go to k12??

Chemistry
1 answer:
DiKsa [7]3 years ago
6 0
I use to
but i live live in Vriginia now.
and im 17 
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What is the purpose of the inert electrode?
azamat
The purpose for the "inert electrode" is quite obvious and also, it's spelled in it's name it's self. The purpose for this would be the first, "conduct electrons". This would be the purpose of this inert electrode, to conduct that electrons at the give time.

<span>A.to create a solution of anions
B. to create a solution of cations
C.to conduct electrons
D. to conduct protons</span>
5 0
4 years ago
Read 2 more answers
what is the concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 m dextrose solution to 25 ml using a 25 ml
allsm [11]

The concentration of a dextrose solution prepared by diluting 14 ml of a 1.0 M dextrose solution to 25 ml using a 25 ml volumetric flask is 0.56M.

Concentration is defined as the number of moles of a solute present in the specific volume of a solution.

According to the dilution law, the degree of ionization increases on a dilution and it is inversely proportional to the square root of concentration. The degree of dissociation of an acid is directly proportional to the square root of a volume.

M₁V₁=M₂V₂

Where, M₁=1.0M, V₁=14ml, M₂=?, V₂=25ml

Rearrange the formula for M₂

M₂=(M₁V₁/V₂)

Plug all the values in the formula

M₂=(1.0M×14 ml/25 ml)

M₂=14 M/25

M₂=0.56 M

Therefore, the concentration of a dextrose solution after the dilution is 0.56M.

To know more about dilution

brainly.com/question/18566203

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6 0
1 year ago
Which of the following is an acid-base neutralization reaction?
ZanzabumX [31]

Answer:

Explanation:

Answer: D

STRONG ACIDS:

HBr

HCl

HI

HNO3

HClO4

H2SO4

8 0
3 years ago
How many moles are contained in a 4.67-l sample of gas at 30°c and 199 kpa?
ohaa [14]
Pv=nRT
where,p=199, R(constant)=8.314, V=4.67 T=30C=293K
n=pv/RT=0.38 moles
4 0
3 years ago
Read 2 more answers
2. Calculate the joules of energy required to heat 454.3g of water<br> frum 5.4°C to 98.6°C.
Tasya [4]

Answer:

176984.38J

Explanation:

E = mC∆T

Where E is the energy in joules

M is the mass of water

C is the specific heat capacity of water =4.184J/g°C

It is known that it will take 4.184J of energy to change the temperature of water by one degree Celsius.

∆T = 98.6°c - 5.4°c

= 93.2°c

∆H = 454.3g × 4.18J/g°C × 93.2°c

= 176984.3768

176984.38J

7 0
4 years ago
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