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3 years ago

Identify the Brønsted-Lowry acid, the Brønsted-Lowry base, the conjugate acid, and the conjugate base in each reaction:

Chemistry

1 answer:

ExtremeBDS [4]3 years ago

3 0

Answer:

C5H5N is the base and C5H5NH+ is the conjugate acid

H2O is the acid and OH− is the conjugate base

Explanation:

Hydrogen + is also called a proton

C5H5N is the base because it receives the proton (H+) and C5H5NH+ is its conjugate acid

H2O is the acid because it gives up the proton and OH− is the conjugate base because it is capable of receiving the proton

Answer:

HNO3 is the acid and NO3- is the conjugate base

H2O is the base and H3O+ is the conjugate acid

Explanation

HNO3 is the acid and NO3− is its conjugate base, capable of receiving a proton

H2O is the base because it receives the proton and H3O+ is a conjugate acid capable of giving up the proton.

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A student is examining a bacterium under the microscope. The E. coli bacterial cell has a mass of m = 1.80 fg (where a femtogram

egoroff_w [7]

Answer:

Δx ≥ 1.22 *10^-10m

Explanation:

Step 1: Data given

The E. coli bacterial cell has a mass of 1.80 fg ( = 1.80 * 10^-15 grams = 1.80 * 10^-18 kg)

Velocity of v = 8.00 μm/s (= 8.00 * 10^-6 m/s)

Uncertainty in the velocity = 3.00 %

E. coli bacterial cells are around 1 μm = 10^−6 m in length

Step 2: Calculate uncertainty in velocity

Δv = 0.03 * 8*10^-6 m/s =2.4 * 10^-7 m/s

Step 3: Calculate the uncertainty of the position of the bacterium

According to Heisenberg uncertainty principle,

Δx *Δp ≥ h/4π

Δx *mΔv ≥ h/4π

with Δx = TO BE DETERMINED

with m = 1.8 *10^-18 kg

with Δv = 2.4*10^-7

with h = constant of planck = 6.626 *10^-34

Δx ≥ 6.626*10^-34 / (4π*(1.8*10^-18)(2.4*10^-7))

Δx ≥ 1.22 *10^-10m

6 0

3 years ago

Which of the following is not equal to 0.1 centimeters?

Anon25 [30]

Answer:

c) 10 millimeters (mm)

Explanation:

The unit conversions are as follows:

1 cm = 10 mm (millimeter)

1 cm = 0.01 m (meter)

1 cm = 0.00001 km (kilometer)

1 cm = 10000 μm (micrometer)

Based on the above conversions:

$0.1 cm = \frac{10 mm*0.1 cm}{1 cm} = 0.1 mm$

$0.1 cm = \frac{0.01 m*0.1 cm}{1 cm} = 0.001 m$

$0.1 cm = \frac{0.00001 km * 0.1 cm}{1 cm} = 0.000001 km$

$0.1 cm = \frac{10000 um*0.1cm}{1 cm} =1000 um$

Therefore, 0.1 cm = 10 mm is incorrect instead it is 0.1 mm

8 0

4 years ago

Read 2 more answers

A sample of gas occupies 6. 8 L at 327 c what will be it volume at 27 c if the pressure and number of particles do not change

Vitek1552 [10]

A sample of gas occupies 6. 8 L at 327 c and the volume at 27 c if the pressure and number of particles do not change is 3.401 L.

<h3>What is volume?</h3>

Volume is a measurement of the three-dimensional space that is occupied. Numerous imperial units or the SI-derived units, such as the cubic meter and liter, are frequently used to quantify it numerically (such as the gallon, quart, cubic inch). Volume and the length (cubed) have a symbiotic relationship. The volume of a container is typically thought of as its capacity, not as the amount of the space it takes up. In the other words, the volume is the amount of fluid (liquid or gas) that the container may hold.

Volume was initially measured using naturally occurring vessels of a comparable shape and then with standardized containers. Arithmetic formulas can be used to quickly calculate the volume of the several straightforward three-dimensional shapes. If a formula for shape's boundary is known, it is possible to use integral calculus to determine the volumes of more complex shapes. No object in dimensions of zero, one, or two has volume; in the dimensions of four and above, the hypervolume is a concept similar to the standard volume.

In solving the any gas law problems, kelvin temperature will be used.

kelvin = degree celsius + 273.15

Kelvin = 327 + 273.15

= 600.15 K

Kelvin = 27 + 273.15

= 300.15 K

Given Data;

$V_{1}$ (the initial volume) = 6.8 L $V_{2}$ (the final volume) = ? unknown

$T_{1}$ (the initial temperature = 327 °C $T_{2}$ (the final temperature) = 27 °C

=( 600.15 K) = (300.15 K)

This problem can be solve using the Charles' Law which states that volume is directly proportional to kelvin temperature of gases if amount of gas and pressure are constant. If the temperature decreases, volume decreases.

Formula of the Charles' Law is $\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }$