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Explanation:
Answer:
M = 0.23 M
Explanation:
Given data:
Molarity of solution = ?
Mass of NH₄Br = 4.50 g
Volume of solution = 213 mL (213 mL× 1L /1000 mL = 0.213 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of NH₄Br:
Number of moles = mass/molar mass
Number of moles = 4.50 g / 97.94 g/mol
Number of moles = 0.05 mol
Molarity:
M = 0.05 mol/ 0.213 L
M = 0.23 M
Answer:
About 16.1 grams of oxygen gas.
Explanation:
The reaction between magnesium and oxygen can be described by the equation:

24.4 grams of Mg reacted with O₂ to produce 40.5 grams of MgO. We want to determine the mass of O₂ in the chemical change.
Compute using stoichiometry. From the equation, we know that two moles of MgO is produced from every one mole of O₂. Therefore, we can:
- Convert grams of MgO to moles of MgO.
- Moles of MgO to moles of O₂
- And moles of O₂ to grams of O₂.
The molecular weights of MgO and O₂ are 40.31 g/mol and 32.00 g/mol, respectively.
Dimensional analysis:

In conclusion, about 16.1 grams of oxygen gas was reacted.
You will obtain the same result if you compute with the 24.4 grams of Mg instead:

LEAD is the element that has this electron configuration