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Paha777 [63]
2 years ago
12

a burning candle wax reacts with oxygen. after a glass jar is placed over it, the candle goes out. what is the limiting reactant

?
Chemistry
1 answer:
viktelen [127]2 years ago
6 0

If the candle goes out when a glass jar is placed over it, then oxygen is the limiting reactant.

<h3>What is a limiting reactant?</h3>

The limiting reactant is the reactant that is present in the least amount. When the limiting reactant is exhausted, the reaction comes to a halt.

Thus, if the candle goes out when a glass jar is placed over it, then oxygen is the limiting reactant.

Learn more about limiting reactant:brainly.com/question/14225536?

#SPJ11

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3 years ago
What is the energy change associated with 1.5 mole of D being formed? 
AleksandrR [38]

Answer:

–36 KJ.

Explanation:

The equation for the reaction is given below:

2B + C —› D + E. ΔH = – 24 KJ

From the equation above,

1 mole of D required – 24 KJ of energy.

Now, we shall determine the energy change associated with 1.5 moles of D.

This can be obtained as illustrated below:

From the equation above,

1 mole of D required – 24 KJ of energy

Therefore,

1.5 moles of D will require = 1.5 × – 24 = –36 KJ.

Therefore, –36 KJ of energy is associated with 1.5 moles of D.

3 0
3 years ago
If 73.5 mL of 0.200 M KI(aq) was required to precipitate all of the lead(II) ion from an aqueous solution of lead(II) nitrate, h
frutty [35]

Answer:

There were 0.00735 moles Pb^2+ in the solution

Explanation:

Step 1: Data given

Volume of the KI solution = 73.5 mL = 0.0735 L

Molarity of the KI solution = 0.200 M

Step 2: The balanced equation

2KI + Pb2+ → PbI2 + 2K+

Step 3: Calculate moles KI

moles = Molarity * volume

moles KI = 0.200M * 0.0735L = 0.0147 moles KI

Ste p 4: Calculate moles Pb^2+

For 2 moles KI we need 1 mol Pb^2+ to produce 1 mol PbI2 and 2 moles K+

For 0.0147 moles KI we need 0.0147 / 2 = 0.00735 moles Pb^2+

There were 0.00735 moles Pb^2+ in the solution

3 0
3 years ago
Question 1 of 10
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8 0
3 years ago
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The thickness of a 6.00 cm square piece of Al that has a mass of .842 g and a density of 2.70 g/cm^3
lutik1710 [3]
Volume = Mass / Density
Volume =  .842 / 2.70
Volume = .31185 cubic centimeters
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depth = (.31185 cubic centimeters) / 36
<span><span><span>depth = 0.0086625514 centimeters

(That must be aluminum foil.)

</span> </span></span>





7 0
3 years ago
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