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Paha777 [63]
1 year ago
12

a burning candle wax reacts with oxygen. after a glass jar is placed over it, the candle goes out. what is the limiting reactant

?
Chemistry
1 answer:
viktelen [127]1 year ago
6 0

If the candle goes out when a glass jar is placed over it, then oxygen is the limiting reactant.

<h3>What is a limiting reactant?</h3>

The limiting reactant is the reactant that is present in the least amount. When the limiting reactant is exhausted, the reaction comes to a halt.

Thus, if the candle goes out when a glass jar is placed over it, then oxygen is the limiting reactant.

Learn more about limiting reactant:brainly.com/question/14225536?

#SPJ11

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4 0
2 years ago
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Dalton incorporated the law of conservation of mass into his atomic theory by asserting that
Feliz [49]

Answer:

a. atoms are indivisible. ... atoms can not be destroyed in chemical reactions.

Explanation:

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7 0
2 years ago
The following reaction is exothermic. C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g)C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) Predict the effect (shi
Zigmanuir [339]

Answer:

According to Le Chatelier's principle, increasing the reaction temperature of an exothermic reaction causes a shift to the left and decreasing the reaction temperature causes a shift to the right.

Explanation:

C6H12O6(s) + 6O2(g) ⇌6CO2(g) + 6H2O(g)

We are told that the forward reaction is exothermic, meaning heat is removed from the reacting substance to the surroundings.

According to Le Chatelier's principle,

1. for an exothermic reaction, on increasing the temperature, there is a shift in equilibrium to the left and formation of the product is favoured.

2. if the temperature of the system is decreased, the equilibrium shifts to right and the formation of the reactants is favoured.

3. if the reaction temperature is kept constant, the system is at equilibrium and there is no shift to the right nor to the left.

6 0
3 years ago
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Calculate the ph of a 0.021 m nacn solution. [ka(hcn) = 4.9  10–10]
ohaa [14]

<span>Answer is: pH of solution of sodium cyanide is 11.3.
Chemical reaction 1: NaCN(aq) → CN</span>⁻(aq) + Na⁺<span>(aq).
Chemical reaction 2: CN</span>⁻ + H₂O(l) ⇄ HCN(aq) + OH⁻<span>(aq).
c(NaCN) = c(CN</span>⁻<span>) = 0.021 M.
Ka(HCN) =  4.9·10</span>⁻¹⁰<span>.
Kb(CN</span>⁻) = 10⁻¹⁴ ÷ 4.9·10⁻¹⁰ = 2.04·10⁻⁵<span>.
Kb = [HCN] · [OH</span>⁻] / [CN⁻<span>].
[HCN] · [OH</span>⁻<span>] = x.
[CN</span>⁻<span>] = 0.021 M - x..
2.04·10</span>⁻⁵<span> = x² / (0.021 M - x).
Solve quadratic equation: x = [OH</span>⁻<span>] = 0.00198 M.
pOH = -log(0.00198 M) = 2.70.
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4 0
2 years ago
I WILL MARK THE BRAINLYEST AND GIVE YOU 100 POINTS
Law Incorporation [45]

Answer:

4.0625

Explanation:

1 grams Oxygen to mol = 0.0625 mol

0.0625 x 65 =4.0625

7 0
3 years ago
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