The presence of hydrogen and hydroxyl ions determines the acidic and basic nature of a solution.
<h3>What determine acidic and basic nature of a solution?</h3>
The use of the pH scale is one way of determining the acidic and basic nature of solution. If the pH of a solution is less than 7, it is considered as acidic and if the pH is 7, the solution is neutral.
While if the pH is greater than 7,the solution is basic so we can conclude that the presence of hydrogen and hydroxyl ions determines the acidic and basic nature of a solution.
Learn more about substance here: brainly.com/question/2901507
Yes, <span>Everything follows the law of conservation of mass, no matter what!</span>
Answer is: encasing nuclear waste in containers that are then taken to remote locations.
Nuclear (radioactive) waste is hazardous to all forms of life and the environment.
Long term storage of radioactive waste is needed. It is important the stabilization of the waste into a form which will neither react nor degrade over many years.
If nuclear waste is wasted in atmosphere or into oceans and lagre lakes, eventually it will come in contact with living organisms.
Answer:

Explanation:
Hello there!
In this case, since the radioactive decay is considered as first-order kinetic model, whereby the remaining mass of the radioactive material involves the initial one, the rate constant and elapsed time:

As we were not initially given the rate constant, we can use the half-life to calculate it as follows:

Thus, we can calculated the elapsed time for the given conditions to obtain:

Regards!